Answer:
a. 8.4 ft³
b. 4.44 ft × 2.44 ft × 0.78 ft
Step-by-step explanation:
a. <em>Maximum volume
</em>
We are creating a box with dimensions
l = 6 – 2x
w = 4 – 2x
h = x
V = lwh = x(6 – 2x)(4 – 2x)
We must determine the value of x that makes V a maximum.
One way is to plot the function V = x(6 – 2x)(4 – 2x).
The maximum appears to be at about (0.78, 8.4).
Thus, the maximum volume is 8.4 ft³.
b.<em> Dimensions
</em>
l = 6 – 2 × 0.78 = 6 – 1.56 = 4.44 ft
w = 4 – 2 × 0.78 = 4 – 1.56 = 2.44 ft
h = 0.78 ft
The box with maximum volume has dimensions 4.44 ft × 2.44 ft × 0.78 ft.
It would be the graph with the line at the 3 on the y axis and with points going up 4 and over 1
Answer:
270
Step-by-step explanation:
Note that 1/10 is equal to 0.1
Multiply 2700 with 0.1
2700 x 0.1 = 270
270 is your answer.
~
Answer:
3.32ft
Step-by-step explanation:
The wire and the poles attached to the ground form a right triangle with the length of the wire being the hypotenuse.
Using Pythagoras Theorem:
Hypotenuse²=Adjacent²+Opposite²
6²=5²+x²
x²=36-25
x²=11
x=√11=3.32 ft.
The wires are attached 3.32 ft from the base of the pole on the ground
The distance between the points is ≈6.4