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Hoochie [10]
2 years ago
11

Solve for x 6(4x+1)=78

Mathematics
2 answers:
olga2289 [7]2 years ago
7 0

Answer:

x=3

Step-by-step explanation:

here,

6(4x+1)=78

or,24x+6=78

or,24x=78-6

or,24x=72

<h3>or, x=72/24</h3><h3>or, x=3</h3><h3>SO, THE ANSWER IS: 3.</h3>
FromTheMoon [43]2 years ago
5 0

Answer:

x=3

Step-by-step explanation:

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\dfrac{ \dfrac{x+3}{4x^2-16} }{ \dfrac{2x^2+10x+12}{2x-4} }

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Write the divide fraction horizontally:
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= \dfrac{x+3}{4x^2-16} \div \dfrac{2x^2+10x+12}{2x-4}

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Factorise the numerators and denominators when possible:
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= \dfrac{x+3}{4(x+2)(x-2)} \div \dfrac{ 2(x + 3) (x + 2)}{2(x-2)}

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Convert the divide fraction to multiplication fraction
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= \dfrac{x+3}{4(x+2)(x-2)} \times \dfrac{2(x-2)}{2(x+3)(x+2)}

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Cancel the factors
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= \dfrac{1}{4(x+2)} \times \dfrac{1}{(x+2)}

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Combine to single fraction
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= \dfrac{1}{4(x+2)^2}



4 0
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