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Ghella [55]
3 years ago
10

Michael arranged his pennies in the following display what is the answer

Mathematics
1 answer:
Vinil7 [7]3 years ago
4 0
You did not show the display im so sorry :(
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Which of the following expressions is not equivalent to -4.5 • -8?
strojnjashka [21]

Answer: (8)(-4.5)

Step-by-step explanation: If you were to multiply -4.5 • -8 it would be a positive number but if you multiply (8)(-4.5) that would equal a negative number

5 0
3 years ago
It has two what y equals so idk which one to solve or plug in(...I'm running out of points...)
Virty [35]
Just plug in one of the other (doesn't matter which one) so it will look like
-3x+6=5x+38
or
5x+38=-3x+6 (it's the same thing as the first one)
Then you solve for x and you substitute that value so you can get y.
Hope this helped :)
4 0
3 years ago
Read 2 more answers
Need help due tomorrow plese
Sav [38]
The answers to the questions

4 0
3 years ago
45 = w − 54 What is the android
Eduardwww [97]

Answer:

w = 99

Step-by-step explanation:

45 = w - 54

99 = w

<em>good luck, i hope this helps :)</em>

4 0
2 years ago
Read 2 more answers
A rectangular field has dimensions of (2x-3) yards and (x+4) yards. the area of the field is 285 square yards. what are the leng
trasher [3.6K]

The area of a rectangle is given by the multiplication of its dimensions:

\text{Area} = \text{width} \times \text{length}

In this case, we have an exact value for the area, and two variable expressions for width and length. Let's replace the formula above with what we're given:

285 = (2x-3)(x+4)

If you expand the right hand side, you have

285 =  2 x^2+ 5 x-12

And if you move all terms to the right hand side, this becomes

0 =  2 x^2+ 5 x-297

This is a quadratic equation, since it is in the form ax^2+bx+c=0, where a = 2,\ b=5 \text{ and } c = -297

If you plug these values in the generic formula

x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

you get

x = \dfrac{-27}{2} \text{  or  } x = 11

Let's see which dimensions they yield:

x = \dfrac{-27}{2} \implies 2x-3 = -30,\quad x+4 = \dfrac{-19}{2}

But the dimensions of a rectangle can't be negative, so we can't accept this answer.

The other solution yields

x = 11 \implies 2x-3 = 19,\quad x+4 = 15

So these are the dimensions of the rectangle

6 0
3 years ago
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