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Sophie [7]
3 years ago
14

Please help me I need it.

Mathematics
2 answers:
Elina [12.6K]3 years ago
8 0

Answer:

NOPE

Step-by-step explanation:

vaieri [72.5K]3 years ago
6 0

Answer:

200g of sugar, 600g of flour, 400g of butter

Step-by-step explanation:

50g sugar = 15 biscuits

3 x 50g = flour --) 150g = flour

2 x 50g = butter --) 100g = butter

60/15 = 4; 4 times as much

4 x 50g = 200g of sugar

4 x 150g = 600g of flour

4 x 100g = 400g of butter

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Twice c is at least 19
Sliva [168]
<h3><u>The value of c is greater than or equal to the value 9.5</u></h3>

2c ≥ 19

We can treat this inequality like a standard algebraic equation.

<em><u>Divide both sides by 2.</u></em>

c ≥ 9.5

7 0
3 years ago
A box of nails weighs 1-5/6 pounds. What is the weight of 12 boxes?
pychu [463]
12 boxes would be 22 pounds.
7 0
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Given the following geometric sequence, find the common ratio: {16, 64, 256, ...}.
Anettt [7]

Answer:

The common ratio is 4

Step-by-step explanation:

We need to divide a term by the previous term to find the common ratio in a geometric sequence:

64 ÷ 16 = 4

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3 years ago
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a 175cm tall student casts a shadow that is 2.3cm long. at the same time, a tree casts a shadow that is 8.2m longest
Anika [276]

Ok so I’m assuming the question is how the tall is we need to find the Angle of the sun so

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Shadow: 2.3

Hypotenuse: 175.0151136

Using -cos(175/175.0151136) we find the

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8 0
3 years ago
Math answer with work cause it need proof ASAP
Viktor [21]

Answer:

[See Below]

Step-by-step explanation:

__________________________

✦ Solve for (1*10)+(4*1)+(7*0.01)+(2*0.001):

__________________________

✦ Solve Parenthesis first:

  • (1*10)=\bold1\bold0
  • (4*1)=\bold4
  • (7*0.01)=\bold0\bold.\bold0\bold7
  • (2*0.001)=\bold0\bold.\bold0\bold0\bold2

__________________________

✦ Add all the values together:

  • 10+4+0.07+0.002=\bold1\bold4\bold.\bold0\bold7\bold2

__________________________

So Mikayla wrote the decimal correctly.

__________________________

~<em>Hope this helps Mate. If you need anything feel free to message me.</em>

-Your~ Friendly ~Answerer,~ Shane ☺

5 0
3 years ago
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