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3 years ago

Please help!!! A(b) is a function. A. True B. False

Mathematics

2 answers:

vazorg [7]3 years ago

4 0

Your answer is false If that Is for 2020

ser-zykov [4K]3 years ago

4 0

It is true my fam at least when i asked my math teacher.

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What is the following sum?<br> 4(^5sqrtx^2y) + 3(^5sqrtx^2y)

Schach [20]

Answer:

option 3

Step-by-step explanation:

$(4 + 3) \sqrt[5]{x {}^{2}y } = 7 \sqrt[5]{ {x}^{2}y }$

7 0

3 years ago

Read 2 more answers

Janice is building a fence around a portion of her rectangular yard. The length of yard she will enclose is x, and the width is

Kipish [7]

We are given

length of rectangular yard is x

so, $L=x$

width of rectangular yard is

so, $W=2x^2-98x+5$

We are given

the length of the enclosed yard is 50 feet

so, we get

$L=x=50$

now, we can plug x=50 and then we can find width

$W=2(50)^2-98(50)+5$

$W=105$

now, we can find total fencing length

so, total fencing length is

$=2L+2W$

now, we can plug values

$=2\times 50+2\times 105$

$=310feet$

now, we are given

the cost of fencing is $13 per foot

so,

total cost = (cost of fencing)*(total fencing length)

we can plug values

$C=13\times 310$

$C=4030$

So, Janice will spend $4030.........Answer

6 0

3 years ago

A ladder 20 feet long is leaning against the wall of a house. The base of the ladder is pulled away from the wall at a rate of 2

alukav5142 [94]

Answer:

0.17 °/s

Step-by-step explanation:

Since the ladder is leaning against the wall and has a length, L and is at a distance, D from the wall. If θ is the angle between the ladder and the wall, then sinθ = D/L.

We differentiate the above expression with respect to time to have

dsinθ/dt = d(D/L)/dt

cosθdθ/dt = (1/L)dD/dt

dθ/dt = (1/Lcosθ)dD/dt where dD/dt = rate at which the ladder is being pulled away from the wall = 2 ft/s and dθ/dt = rate at which angle between wall and ladder is increasing.

We now find dθ/dt when D = 16 ft, dD/dt = + 2 ft/s, and L = 20 ft

We know from trigonometric ratios, sin²θ + cos²θ = 1. So, cosθ = √(1 - sin²θ) = √[1 - (D/L)²]

dθ/dt = (1/Lcosθ)dD/dt

dθ/dt = (1/L√[1 - (D/L)²])dD/dt

dθ/dt = (1/√[L² - D²])dD/dt

Substituting the values of the variables, we have

dθ/dt = (1/√[20² - 16²]) 2 ft/s

dθ/dt = (1/√[400 - 256]) 2 ft/s

dθ/dt = (1/√144) 2 ft/s

dθ/dt = (1/12) 2 ft/s

dθ/dt = 1/6 °/s

dθ/dt = 0.17 °/s

8 0

3 years ago

Solve for Z. <br><br> 3z - 5 = 2z + 2

inna [77]

The answer to your equation is z = 7

7 0

3 years ago

Marely walked around 2 rectangular parks. One measures 54 feet by 38 feet and the other measures 32 feet by 22 feet.

galben [10]

Answer:

130 feet or 39.6m

Step-by-step explanation:

for Marely's first rectangular park, L=54 and B= 38

Total perimeter of distance walked in first rectangular park is 2(L+B), which is 2(54+38) =184 feet

For Marely's second rectangular park, L= 32 and B=22

Total perimeter of second distance 2(L+B), which is 2(32+22) = 108 feet

Total perimeter covered by Marely = (P1+P2) 184+108 = 292 feet

Marely's brother = 2(L+B)

2(48+33) = 162 feet

Hence, difference is 292-162 = 130 feet or 39.6m

3 0

3 years ago