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3 years ago

{UNIT RATES} A punch recipe calls for 2/3 of a pint of fruit juice for each pint of soda.

Mathematics

2 answers:

Julli [10]3 years ago

7 0

Well the ratio will be 2:3

Naily [24]3 years ago

3 0

The ratio of soda to fruit juice in the punch is 1 to 2/3

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There are 3 different mathematics courses, 3 different science courses, and 5 different history courses. If a student must take

Damm [24]

Answer:

45 ways

Step-by-step explanation:

We are given;

there are 3 different math courses, 3 different science courses, and 5 different history courses.

Thus;

Number ways to take math course = 3

The number of ways to take science course = 3

The number of ways to take history course = 5

Now, if a student must take one of each course, the different ways it can be done is;

possible ways = 3 x 3 x 5 = 45 ways.

Thus, number of different ways in which a student must take one of each subject is 45 ways.

3 0

3 years ago

I need help please and thank you

taurus [48]

Answer:

are you on edge

Step-by-step explanation:

5 0

3 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

3 years ago

WHAT IS 0-0 NEED HELP ASAPPPPP ROCKEY PLS WILL MAKR BRAINLIEST

pshichka [43]

Answer: its 0 right or is it supposed to be a face or sumthin

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A right cylindrical solid is cut in half to form the figure

Paha777 [63]

Answer: B) (96pi + 160) cm2

Step-by-step explanation:

7 0

3 years ago