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3 years ago

I dont understand help me

Mathematics

1 answer:

DochEvi [55]3 years ago

4 0

1.5x=3

First you want to get x by itself so divide both sides by 1.5

3/1.5=2
x=2

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Suppose Eric and Isaac both drive the same car, and have the same

Leto [7]

Answer:

eric

Step-by-step explanation:

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5 0

3 years ago

Read 2 more answers

Sue has 20 biscuits in a tin There are 12 plain biscuits 5 chocolate biscuits 3 currant biscuits Sue takes at 2 random biscuits

vagabundo [1.1K]

Answer:

111 / 190

Step-by-step explanation:

Total biscuits = 20

Plain, P = 12

Chocolate, C = 5

Currant, K = 3

Assume without replacement :

Probability that biscuit are of the same type :

P(plain) :

12 / 20 * 11 / 19 = 132 / 380

P(chocolate) :

5/ 20 * 4 / 19 = 20/ 380

P(currant) :

3/20 * 2 /19 = 6 / 380

Therefore,

Probability that biscuit is of the same type :

P(plain) + P(chocolate) + P(currant)

132/380 + 20/380 + 6/380

158 / 380 = 79 / 190

Therefore, probability that biscuit aren't of the same type :

1 - P(biscuit is of same type)

1 - 79/190

(190 - 79) / 190

111 / 190

7 0

2 years ago

Perform the indicated operation. 11(-2) 22 9 -9 -22

ASHA 777 [7]

Answer:

-22

Step-by-step explanation:

When you multiply a positive and negative number together, it becomes negative.

Multiplication is repetitive addition.

11(-2) = -11 + -11 = -22

3 0

3 years ago

Factor this expression completely. 39x − 52y + 13

Jet001 [13]

Answer:

13(3x-4y+1)

Step-by-step explanation:

Rewrite 52 as (4)(13)

Rewrite 39 as (3)(13)

$=(3*13)x+(4*13)y+13$

Then factor out the common term 13

$13(3x-4y+1)$

That is your answer!

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3 years ago

Read 2 more answers

Recent census data indicated that 14.2% of adults between the ages of 25 and 34 live with their parents. A random sample of 125

kicyunya [14]

Answer:

The probability is $P(14 < X < 20 ) = 0.5354$

Step-by-step explanation:

From the question we are told that

The proportion that live with their parents is $\r p = 0.142$

The sample size is n = 125

Given that there are two possible outcomes and that this outcomes are independent of each other then we can say the Recent census data follows a Binomial distribution

i.e

$X \ \~ \ B( \mu , \sigma )$

Now the mean is evaluated as

$\mu = n * \r p$

$\mu = 125 * 0.142$

$\mu = 17.75$

Generally the proportion that are not staying with parents is

$\r q = 1 - \r p$

= > $\r q = 0.858$

The standard deviation is mathematically evaluated as

$\sigma = \sqrt{n * \r p * \r q }$

$\sigma = \sqrt{ 125 * 0.142 * 0.858 }$

$\sigma = 3.90$

Given the n is large then we can use normal approximation to evaluate the probability as follows

$P(14 < X < 20 ) = P( \frac{ 14 - 17.75}{3.90}$

Now applying continuity correction

$P(14 < X < 20 ) = P( \frac{ 13.5 - 17.75}{3.90} < \frac{ X - \mu }{\sigma } < \frac{ 19.5 - 17.75}{3.90} )$

Generally

$\frac{ X - \mu }{\sigma } = Z ( The \ standardized \ value \ of X )$

$P(14 < X < 20 ) = P( \frac{ 13.5 - 17.75}{3.90} < Z< \frac{ 19.5 - 17.75}{3.90} )$

$P(14 < X < 20 ) = P( -1.0897 < Z< 0.449 } )$

$P(14 < X < 20 ) = P( Z< 0.449 ) - P(Z < -1.0897)$

So for the z - table

$P( Z< 0.449 ) = 0.67328$

$P(Z < -1.0897) = 0.13792$

$P(14 < X < 20 ) = 0.67328 - 0.13792$

$P(14 < X < 20 ) = 0.5354$

6 0

3 years ago