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IRISSAK [1]
2 years ago
7

Give the algebraic expression by using variables and constant and arithmetic operations: i. Sum of the squares of x and y. ii.Pr

oduct of "x" and "y" subtracted from 9. Pls fast
Mathematics
1 answer:
Olenka [21]2 years ago
5 0

Answer:

a) x^2 + y^2

b) 9-xy

Step-by-step explanation:

Here, we want to write the algebraic statements as expressions;

a) The sum of the squares of x and y

The square of x is x^2

The square of y is y^2

The sum of the squares is x^2 + y^2

ii) Product of x and y subtracted from 9

The product of x and y is x * y = xy

Subtracting these from 9, we have;

9-xy

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Step-by-step explanation:

high school with pariantal consent

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3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D" id="TexFormula1" title="\frac{1}{3}" alt="\frac{1}{3}" align="absmiddle
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The resulting fractions is 14/15

<h3>Solving equations</h3>

Given the expression shown below;

1/3 +  2/5(2 - 1/2)^2

Solve the expression in bracket

1/3 + 2/5(3/2)^2

1/3 + 2/5(9/4)

Multiply the fractions

1/3 + 18/20

Find the LCM

20+36/60

56/60

28/30

14/15

Hence the resulting fractions is 14/15

Learn more on fractions here; brainly.com/question/78672

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3 0
1 year ago
Who could help me? I do not understand the question
Brut [27]
D. is the correct answer because vertical angles are always equal. 
4 0
3 years ago
Please help I need help
navik [9.2K]

Answer:

L=10pi, or 31.42

Step-by-step explanation:

4 0
2 years ago
The graph of a function f(x) passes through the following points:
Alex

The function is f(x) = -2x² + 2 if the function f(x) passes through the following points:(0,2), (1, 0), (-1,0)

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have:

The graph of a function f(x) passes through the following points: (0,2), (1, 0), (-1,0)

Let

f(x) = ax² + bx + c

Plug x = 0, and y = 2

c = 2 ...(1)

Plug x = 1 and y = 0

a + b + c = 0 ..(2)

Plug x = -1 and y = 0

a - b + c = 0  ...(3)

After solving (1), (2), and (3)

a = -2

b = 0

c = 2

f(x) = -2x² + 2

Thus, the function is f(x) = -2x² + 2 if the function f(x) passes through the following points:(0,2), (1, 0), (-1,0)

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

5 0
1 year ago
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