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2 years ago

I have absolutely no idea what I am doing so yeah pls help me lol.

Mathematics

2 answers:

Pani-rosa [81]2 years ago

8 0

Answer:

The answer is D

Step-by-step explanation: Trust me! hope this helps:)

Digiron [165]2 years ago

3 0

Answer:

Option D

Dilation with scale factor 2, multiply by 2.

(x, y) → (2x,2y)

Step-by-step explanation:

J(2,4) → J'(4,8)

K(1,1) → K'(2,2)

L(4,0) → L'(8,0)

Dilate with a scale factor of 2

Each set of JKL points multiplied by 2 to form J'K'L'

J(2*2, 2*4)

K(2*1, 2*1)

L(2*4, 2*0)

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The given expression is $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$

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Option A: -1

Solving the expression, we get;

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Option B: 29

Solving the expression, we get;

$\frac{3}{2} x+14-\frac{3}{2} x+15$

Simplifying, we get;

$14+15=29$

Thus, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent to 29.

Hence, Option B is the correct answer.

Option C: $2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Let us rewrite the given expression.

$2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Thus, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent to $2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Thus, Option C is the correct answer.

Option D: $2\left(\frac{3}{4} x\right)+2(7)+3\left(\frac{1}{2} x\right)+3(-5)$

Rewriting the expression, we get;

$2\left(\frac{3}{4} x+7\right)+(-3)\left[\frac{1}{2} x+(-5)\right]$

Hence, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent not to $2\left(\frac{3}{4} x\right)+2(7)+3\left(\frac{1}{2} x\right)+3(-5)$

Thus, Option D is not the correct answer.

Option E: $2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)$

Multiplying the terms within the bracket, we get;

$2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)$

Hence, the expression $2\left(\frac{3}{4} x+7\right)-3\left(\frac{1}{2} x-5\right)$ is equivalent to $2\left(\frac{3}{4} x\right)+2(7)+(-3)\left(\frac{1}{2} x\right)+(-3)(-5)$

Thus, Option E is the correct answer.

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