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4 years ago

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Physics

1 answer:

Artemon [7]4 years ago

7 0

Explanation:

At a height of 93 m, the gravitational potential energy is given by :

P = mgh

Where, m is the mass of a penny

We can find its mass.

$m=\dfrac{P}{gh}\\\\m=\dfrac{3}{9.8\times 93}\\\\m=0.00329\ kg$

We need to find how much potential energy will have transformed into kinetic energy at the half way point (46.5m). It can be calculated as :

$E=mgh'\\\\E=0.00329\times 9.8\times 46.5\\\\E=1.499\ J$

Hence, a penny will have transferred 1.499 J of potential energy into kinetic energy.

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An electron and a proton are each placed at rest in a uniform electric field of magnitude 560 N/C. Calculate the speed of each p

Butoxors [25]

Answer:

The speed of electron is $v=4.52\times 10^6\ m/s$ and the speed of proton is 2468.02 m/s.

Explanation:

Given that,

Electric field, E = 560 N/C

To find,

The speed of each particle (electrons and proton) 46.0 ns after being released.

Solution,

For electron,

The electric force is given by :

$F=qE$

$F=1.6\times 10^{-19}\times 560=8.96\times 10^{-17}\ N$

Let v is the speed of electron. It can be calculated using first equation of motion as :

$v=u+at$

u = 0 (at rest)

$v=\dfrac{F}{m}t$

$v=\dfrac{8.96\times 10^{-17}}{9.1\times 10^{-31}}\times 46\times 10^{-9}$

$v=4.52\times 10^6\ m/s$

For proton,

The electric force is given by :

$F=qE$

$F=1.6\times 10^{-19}\times 560=8.96\times 10^{-17}\ N$

Let v is the speed of electron. It can be calculated using first equation of motion as :

$v=u+at$

u = 0 (at rest)

$v=\dfrac{F}{m}t$

$v=\dfrac{8.96\times 10^{-17}}{1.67\times 10^{-27}}\times 46\times 10^{-9}$

$v=2468.02\ m/s$

So, the speed of electron is $v=4.52\times 10^6\ m/s$ and the speed of proton is 2468.02 m/s. Therefore, this is the required solution.

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