Answer:
earthquake activity is the answer
Answer:
0.084 kg
Explanation:
I = 0.80 N-s (East wards) = 0.80 i N-s
u = 3.8 m/s = - 3.8 i m/s
v = 5.7 m/s = 5.7 i m/s
Let m be the mass of bat.
I = m (v - u)
0.8 i = m ( 5.7 i + 3.8 i)
0.8 i = m x 9.5 i
m = 0.084 kg
Answer:
Newton's Cradle experiment perfectly demonstrates the law of conservation of momentum which states that in a closed system, momentum before the collision is equal to momentum after the collision of the system.
As the first ball swings in the air, it gains momentum. When it strikes the second ball, it loses momentum and second ball gains equal amount of momentum. The second ball transfers the momentum to third, then fourth and till the last. The last ball when gains the same momentum swings up in the air. This continues. This experiment is done in drag free condition. This means there is no loss of momentum or opposing forces present.
I think this is the answer hope it helps
Answer:
Truck's speed = 5.21 m/s
Car's speed = 20.2 m/s
Explanation:
Given:
Mass of truck = M = 1650 kg
Speed of the truck initially = U = 15 m/s
Mass of the car = m = 779 kg
Initial speed of the car =u = 0
From the momentum conservation, Total initial momentum = Total final momentum.
M V+m U = M V +m v
⇒ (1650)(15) + 779×0 = (1650)V + 779 v
⇒ 24750 = 1650 V+779 v →(1)
Since the collision is elastic, relative velocity of approach = relative velocity of separation. 15 = v - V
⇒ v =V + 15; This is now substituted in the equation(1) above.
24750 = 1650 V + (799) (V+15)
⇒ 24750 = 1650 V + 799 V + 11985
⇒ 2449 V = 12765
⇒ Final velocity of the truck =
= 5.21 m/s
Final velocity of the car = v = V+15 = 5.21 + 15 = 20.2 m/s