There are 15 oranges
<em><u>Solution:</u></em>
Let "x" be the number of oranges
Let "y" be the number of pears
Let "c" be the number of children
<em><u>There are 3 times as many pears are oranges</u></em>
Number of pears = 3 times the number of oranges
y = 3x -------- eqn 1
<u><em>If a group of children receive 5 oranges each, there will be no left over</em></u>
So, "c" children receives 5 oranges each, there will be no left over
number of oranges = 5(number of children)
x = 5c ------- eqn 2
<em><u>If the same group of children receive 8 oranges each, there will be 21 pears left over</u></em>
number of pears = 8 oranges(number of children) + 21
y = 8c + 21
<em><u>Substitute eqn 1</u></em>
3x = 8c + 21 ---- eqn 3
<em><u>Substitute eqn 2</u></em>
3(5c) = 8c + 21
15c - 8c = 21
7c = 21
c = 3
<em><u>Substitute c = 3 in eqn 2</u></em>
x = 5(3)
x = 15
Thus there are 15 oranges
