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3 years ago

Write 0.00034 as a multiple of a power of 10.

Mathematics

2 answers:

adelina 88 [10]3 years ago

7 0

3.4*10^-4
hope this helps!!

borishaifa [10]3 years ago

3 0

Answer:

3.4X10^-4

remove the zeros and add a decimal point after the first number eg.

<u>0.000</u>34 --> 34 --> 3.4

then add a x 10 eg.

3.4x10

then add a power- if the number is larger than 1 count the amount of zeros and add that as your power eg.

3400 -> 34 -> 3.4 -> 3.4x10^2

If the number is lower than one use a negative power eg.

0.00034 -> 34 -> 3.4 -> 3.4x10^-4

(Hope this helps sorry if its to complicated)

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Simplify to a single power of 3:<br><br> 3^6 x 3

guapka [62]

Answer:
I am not sure what you mean by simplifying to a single power of 3 but 3^6 x 3 would be the power 3 over 7 = 3^7

5 0

3 years ago

Please answer this question correctly for 25 points and brainliest!!

lesya692 [45]

Step-by-step answer:

Given an enlargement from preimage (ABC) to image (A'B'C').

Need to find scale factor.

Solution:

Scale factor = linear size of image / linear size of preimage.

From the accompanying diagram, we see that

L(preimage) = AC = 4 units

L(image) = A'C' = 12 units

Therefore

Scale factor = L(image) / L(preimage) = 12 / 4 = 3

4 0

3 years ago

A parabola has a focus of F(2, -0.5) and a directrix of y=-1.5 P(x,y) represents any point on the parabola, while D(x, -1.5) rep

prohojiy [21]

The sketch of the parabola is attached below

We have the focus $(a,b) = (2, -0.5)$
The point $P(x,y)$
The directrix, c at $y=-1.5$

The steps to find the equation of the parabola are as follows

Step 1
Find the distance between the focus and the point P using Pythagoras. We have two coordinates; $(2, -0.5)$ and $(x,y)$ .
We need the vertical and horizontal distances to find the hypotenuse (the diagram is shown in the second diagram).
The distance between the focus and point P is given by
$\sqrt{ (x-a)^{2}+ (y-b)^{2} }$

Step 2
Find the distance between the point P to the directrix $c$ . It is a vertical distance between y and c, expressed as $y-c$

Step 3
The equation of parabola is then given as
$\sqrt{ (x-a)^{2}+ (y-b)^{2} }$ = $y-c$
$(x-a)^{2}+ (y-b)^{2}= (y-c)^{2}$ ⇒ substituting a, b and c
$(x-2)^{2}+ (y--0.5)^{2} = (y--1.5)^{2}$
$(x-2)^{2}+ (y+0.5)^{2}= (y+1.5)^{2}$ ⇒Rearranging and making $y$ the subject gives

$y= \frac{ x^{2} }{2} -2x+1$