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3 years ago

Evaluate this expression |-9|

Mathematics

2 answers:

serious [3.7K]3 years ago

7 0

Step-by-step explanation:

|-9| = 9 , since the absolute value of every negative number is a positive number

N76 [4]3 years ago

3 0

Answer:9

Step-by-step explanation:

The distance between-9 and 0 is 9.

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Last night, the temperature fell from 0°F to –131 5 in 42 5 hours. What was the average temperature change per hour? Solve the d

Tcecarenko [31]

Answer:

-3.09 per hour

Step-by-step explanation:

if you mean that it went down from 0° to -131.5° in 42.5 hours, divide -131.5 by 42.5 (-131.5/42.5) which gives 3.09

6 0

3 years ago

Read 2 more answers

What is the quotient when 4x3 + 2x + 7 is divided by x + 3?

Arte-miy333 [17]

Answer:

The quotient of this division is $(4x^2 -12x + 38)$ . The remainder here would be $-26$ .

Step-by-step explanation:

The numerator $4x^3 + 2x + 7$ is a polynomial about $x$ with degree $3$ .

The divisor $x + 3$ is a polynomial, also about $x$ , but with degree $1$ .

By the division algorithm, the quotient should be of degree $3 - 1 = 2$ , while the remainder shall be of degree $1 - 1 = 0$ (i.e., the remainder would be a constant.) Let the quotient be $a\,x^2 + b\, x + c$ with coefficients $a$ , $b$ , and $c$ .

$4x^3 + 2x + 7 = \left(a\,x^2 + b\, x + c\right)(x + 3)$ .

Start by finding the first coefficient of the quotient.

The degree-three term on the left-hand side is $4 x^3$ . On the right-hand side, that would be $a\, x^3$ . Hence $a = 4$ .

Now, given that $a = 4$ , rewrite the right-hand side:

$\begin{aligned}&\left(4\,x^2 + b\, x + c\right)(x + 3) \cr =& \left(4x^2 + (b\, x + c)\right)(x + 3) \cr =& 4x^2(x + 3) + (bx + c)(x + 3) \cr =& 4x^3 + 12x^2 + (bx + c)(x + 3)\end{aligned}$ .

Hence:

$4x^3 + 2x + 7 = 4x^3 + 12x^2 + (b\,x + c)(x + 3)$

Subtract $\left(4x^3 + 12x^2\right$ from both sides of the equation:

$-12x^2 + 2x + 7 = (b\,x + c)(x + 3)$ .

The term with a degree of two on the left-hand side has coefficient $(-12)$ . Since the only term on the right hand side with degree two would have coefficient $b$ , $b = -12$ .

Again, rewrite the right-hand side:

$\begin{aligned}&\left(-12 x + c\right)(x + 3) \cr =& \left(-12 x+ c\right)(x + 3) \cr =& (-12x)(x + 3) + c(x + 3) \cr =& -12x^2 -36x + (bx + c)(x + 3)\end{aligned}$ .

Subtract $-12x^2 -36x$ from both sides of the equation:

$38x + 7 = c(x + 3)$ .

By the same logic, $c = 38$ .

Hence the quotient would be $(4x^2 - 12x + 38)$ .

6 0

3 years ago

NEED ANSWER NOW!!

nydimaria [60]

The answer would be letter B. You can see that the price of the demanded products as the time passes by decreases. So the answer is letter B.

6 0

3 years ago

Read 2 more answers

PLEASEEEE HELP MEEE

kobusy [5.1K]

The 1st , 3rd , 5th and 6th apply

6 0

2 years ago

Solve −2x2 +3x − 9 = 0

luda_lava [24]

-2x^2 + 3x - 9 = 0
The quadratic is not factorable so quadratic formula must be used.
x = (-b + - √(b^2 - 4ac))/2a
a = -2, b = 3, c = -9
x = (-3 + - √(9 - 4*-2*-9))/-4
x = (-3 + - √(-63))/-4
x = -3 + - 3i√7
   --------------
   -4
x = 3 + 3i√7 x = 3 - 3i√7
    ------------ ------------
   4 4

8 0

3 years ago