Answer:
∫ₑ°° 1 / (x (ln x)¹⁰) dx
∫₁°° x⁻³ dx
Step-by-step explanation:
A p-series 1 / xᵖ converges if p > 1.
∫ₑ°° 1 / (x (ln x)¹⁰) dx
If u = ln x, then du = 1/x dx.
When x = e, u = 1. When x = ∞, u = ∞.
= ∫₁°° 1 / (u¹⁰) du
p = 10, converges
∫₁₀°° x^(-⅔) dx
= ∫₁₀°° 1 / (x^⅔) dx
p = ⅔, diverges
∫₁°° 2 / x^0.5 dx
= 2 ∫₁°° 1 / x^0.5 dx
p = 0.5, diverges
∫₁°° x⁻³ dx
= ∫₁°° 1 / x³ dx
p = 3, converges
∫₂°° 1/(3x) dx
= ⅓ ∫₂°° 1/x dx
p = 1, diverges
Answer:
y=17/3
Step-by-step explanation:
So you should make one -3y positive to cancel them out.
So multiply 2x-3y=43 by -1 and you get
-2x+3y=43
4x-3y=83
now +3y -3y cancel each other out
4x-2x=83-43
2x=50
x=25
Now enter 25 into the equation as x to find y
4(25)-3y=83
100-3y=83
100-83=3y
3y=17
y=17/3
The probability that neither of the sample of 2 is good is:
The probability that at least one is good is:
P(at least one is good) = 1 - 0.479 = 0.521
First you turn the toot functions into exponents (square root = 1/2, cubed root = 1/3, fifth root = 1/5 etc). Then you use exponent laws to simplify.
No. If it is not an integer, it cannot include 1, 2, 3, 4, 5... etc. Since integers include whole numbers, this is not possible.