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grandymaker [24]
3 years ago
7

Which system of equations can be used to find the roots of the equation 12x3-5x=2x2+x+6

Mathematics
2 answers:
Marizza181 [45]3 years ago
7 0
Same=same figure out what the x is both x are the same number on both side is the same answer hope that helps
seraphim [82]3 years ago
7 0

y=12x^{3}-5x -----> equation A

y=2x^{2} +x+6 ------> equation B

we have

12x^{3}-5x=2x^{2} +x+6

This equation can be rewritten in the following system of equations

y=12x^{3}-5x -----> equation A

y=2x^{2} +x+6 ------> equation B

we know that

The solution of the system of equations is the intersection point both graphs

using a graphing tool

see the attached figure

The solution is

x=1.07



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Answer:

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Step-by-step explanation:

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\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

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