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grandymaker [24]
4 years ago
7

Which system of equations can be used to find the roots of the equation 12x3-5x=2x2+x+6

Mathematics
2 answers:
Marizza181 [45]4 years ago
7 0
Same=same figure out what the x is both x are the same number on both side is the same answer hope that helps
seraphim [82]4 years ago
7 0

y=12x^{3}-5x -----> equation A

y=2x^{2} +x+6 ------> equation B

we have

12x^{3}-5x=2x^{2} +x+6

This equation can be rewritten in the following system of equations

y=12x^{3}-5x -----> equation A

y=2x^{2} +x+6 ------> equation B

we know that

The solution of the system of equations is the intersection point both graphs

using a graphing tool

see the attached figure

The solution is

x=1.07



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3 years ago
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Jason received $25 dollars from his grandmother. Jason's sister received $5 dollars more than Jason. Write an equation.
KiRa [710]

Answer: J(25) + JS(5) = 30

Step-by-step explanation:

J = Jason

JS = Jason Sister.

7 0
3 years ago
If f(x) = 3x2 – 12x + 4, find f(–2).<br> A) -40 <br> B) -20 <br> C) 20 <br> D) 40
Digiron [165]

Answer:

The answer is D

Step-by-step explanation:

f(x) = 3x² - 12x + 4

f(-2) = 3(-2)² - 12(-2) + 4

= 12 + 24 + 4

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8 0
3 years ago
Braving blizzard conditions on the planet Hoth, Luke Skywalker sets out at top speed in his snowspeeder for a rebel base 4800 mi
____ [38]

Answer:

v_top = 2400 mi/hr

v_w = 400 mi/h

Step-by-step explanation:

Given:

- Total distance D = 4800 mi

- Headwind journey time taken t_up= 3 hr

- Tailwind journey time taken t_down = 2 hr

Find:

Find the top speed of Luke's snow speeder and the speed of the wind.

Solution:

- The speed of Luke v_l is in stationary frame is given by:

                           v_l = v_w + v_l/w

Where,

           v_w: Wind speed

           v_l/w: Luke speed relative to wind.

- The top speed is attained on his returned journey with tail wind. We will use distance time relationship to calculate as follows:

                         v_top = D / t_down

                         v_top = 4800 / 2

                        v_top = v_down = 2400 mi/hr

- Similarly his speed on his journey up with head wind was v_up:

                         v_up = D / t_up

                         v_up = 4800 / 3

                        v_up = 1600 mi/hr    

- Now use the frame relations to find the wind speed v_w:

                         v_down = v_w + v_l/w

                         v_up = -v_w + v_l/w    

- Solve equations simultaneously:

                         2400 =  v_w + v_l/w

                         1600 =  -v_w + v_l/w

                         4000 = 2*v_l/w

                         v_l/w = 2000 mi/h

                         v_w = 400 mi/h

7 0
3 years ago
The 8 has a value of 8 x ?
kobusy [5.1K]
Im confused on what ur asking but maybe it’s 8
5 0
3 years ago
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