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lilavasa [31]
2 years ago
14

There were 57 cars in a parking lot at 9:00 AM and 36 different cars at 8:00 PM.

Mathematics
1 answer:
Dmitry [639]2 years ago
7 0

Answer:

C. 93 cars

Step-by-step explanation:

57 cars + 36 cars = 93 cars

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Answer: 39.22 yd^2 (as in yards squared)

Step-by-step explanation:

1. DO NOT FOCUS ON THE 6! JUST FOCUS ON THE BASE AND HEIGHT!

2. Area= b*h

3. Plus in your numbers. Area=3.7*10.6.

4. Multiply. Area=39.22 yds^2

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3 years ago
X^2 -50x+456=0 solve this algebraiclly find x
bagirrra123 [75]

Answer:

x=-406

Step-by-step explanation:

x^2-50x+456=0

x^2-50x=-456

This is because we subtract 456 from each side.

x-50=-456

We then divide the whole equation by <em>x</em> .

x=-406

Adding 50 to both sides gives us <em>x</em> by itself, hope this helps :D

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HELP PLEASE! <br><br><br><br><br><br>Please explain Slovin's formula​
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Answer:

I need more information, meaning his formula.

Step-by-step explanation:

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2 years ago
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HELPPPP!!!
Hatshy [7]

Answer:

(x - 1)²/4² - (y - 2)²/2² = 1 ⇒ The bold labels are the choices

Step-by-step explanation:

* Lets explain how to solve this problem

- The equation of the hyperbola is x² - 4y² - 2x + 16y - 31 = 0

- The standard form of the equation of hyperbola is

  (x - h)²/a² - (y - k)²/b² = 1 where a > b

- So lets collect x in a bracket and make it a completing square and

  also collect y in a bracket and make it a completing square

∵ x² - 4y² - 2x + 16y - 31 = 0

∴ (x² - 2x) + (-4y² + 16y) - 31 = 0

- Take from the second bracket -4 as a common factor

∴ (x² - 2x) + -4(y² - 4y) - 31 = 0

∴ (x² - 2x) - 4(y² - 4y) - 31 = 0

- Lets make (x² - 2x) completing square

∵ √x² = x

∴ The 1st term in the bracket is x

∵ 2x ÷ 2 = x

∴ The product of the 1st term and the 2nd term is x

∵ The 1st term is x

∴ the second term = x ÷ x = 1

∴ The bracket is (x - 1)²

∵  (x - 1)² = (x² - 2x + 1)

∴ To complete the square add 1 to the bracket and subtract 1 out

   the bracket to keep the equation as it

∴ (x² - 2x + 1) - 1

- We will do the same withe bracket of y

- Lets make 4(y² - 4y) completing square

∵ √y² = y

∴ The 1st term in the bracket is x

∵ 4y ÷ 2 = 2y

∴ The product of the 1st term and the 2nd term is 2y

∵ The 1st term is y

∴ the second term = 2y ÷ y = 2

∴ The bracket is 4(y - 2)²

∵ 4(y - 2)² = 4(y² - 4y + 4)

∴ To complete the square add 4 to the bracket and subtract 4 out

   the bracket to keep the equation as it

∴ 4[y² - 4y + 4) - 4]

- Lets put the equation after making the completing square

∴ (x - 1)² - 1 - 4[(y - 2)² - 4] - 31 = 0 ⇒ simplify

∴ (x - 1)² - 1 - 4(y - 2)² + 16 - 31 = 0 ⇒ add the numerical terms

∴ (x - 1)² - 4(y - 2)² - 16 = 0 ⇒ add 14 to both sides

∴ (x - 1)² - 4(y - 2)² = 16 ⇒ divide both sides by 16

∴ (x - 1)²/16 - (y - 2)²/4 = 1

∵ 16 = (4)² and 4 = (2)²

∴ The standard form of the equation of the hyperbola is

   (x - 1)²/4² - (y - 2)²/2² = 1

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A grocery store chain has been tracking data on the number of shoppers that use coupons. The data shows that 71% of all shoppers
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<span>The computation for the confidence level = (18/20) x 100% = 90 %, the E or the margin error = 0.023 and the p = to 0.71. Confidence interval can be achieved by using the formula (p-E, p+E) = (0.71-0.025, 0.71+0.025). Therefore, the confidence interval is (0.685,0.735).</span>

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