Please help! I will mark brainliest. Sketch the following graphs in order:
1 answer:
Answer:
Domain of f(x) = 2/7x - 2: (-∞, ∞)
Range of f(x) = 2/7x - 2: (-∞, ∞)
Domain of f(x) = |x + 3| - 1: (-∞, ∞)
Range of f(x) = |x + 3| - 1: [-1, ∞)
Domain of f(x) = -5x + 4: (-∞, ∞)
Range of f(x) = -5x + 4: (-∞, ∞)
Step-by-step explanation:
We can use a graphing calculator to find the graphs.
Domain is the set of all x-values that can be inputted into function <em>x</em>.
Range is the set of all y-values that can be outputted from function <em>x</em>.
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Answer:
The turns of a graph is represented by the number of maximum or minimum that the function has.
If we differenciate f(x) we get:
f'(x)=4x^3+6x
f'(x)=2x(2x^2 + 3)
Therefore f'(x) =0, when x=0. Given that negative roots are not defined.
Therefore, the number of turns will be given by the number of solutions of f'(x) which is 1.
Attached you find the graph of the function which confirms the number of turns.
If the function had other solutions, the maximum number of turns it could have is 3! because f'(x) is a third degree polynomial, therefore it can't have more than 3 solutions!
