Answer:
In ∆ABC AND ∆DEF
ABC=DEF...........each 90°
SIDE AB =SIDE ED...........given
SIDE BC =SIDE EF............B-F-C and E-C-F
∆ABC =∆DEF....................by SAS test
Answer:
0.1569 = 15.69%
Step-by-step explanation:
If eight calls were placed, and we need to know the probability of exactly two calls were occupied, we need to calculate a combination of 8 choose 2 (all the combinations of 2 occupied calls in the 8 total calls), and multiply by the probability of each case in the 8 calls (2 cases occupied and 6 cases not occupied):
P(8,2) = C(8,2) * p(occupied)^2 * p(not_occupied)^6
P(8,2) = (8*7/2) * (0.45)^2 * (0.55)^6
P(8,2) = 28 * 0.2025 * 0.02768 = 0.1569 = 15.69%
For this case we are going to define the following variable:
x: time in minutes
We write the linear function that represents the problem:
t (x) = (14/4) x + 7
For x = 6 we have:
t (6) = (14/4) * (6) + 7
t (6) = 28 ° C
For x = 11 we have:
t (11) = (14/4) * (11) + 7
t (11) = 45.5 ° C
Answer:
t (6) = 28 ° C
t (11) = 45.5 ° C
4 hours? i may be wrong
i did - 60 * 15
seems about right, since 50% would be 7.5 hours?
