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VashaNatasha [74]
3 years ago
5

Hat is the solution to the system of equations?

Mathematics
1 answer:
Dima020 [189]3 years ago
5 0

Answer:

(–19, 55)

Step-by-step explanation:

y = –3x – 2   equation 1

5x + 2y = 15 equation 2

using equation 1 in equation 2 we have:

5x + 2(–3x – 2) = 15

5x –6x – 4 = 15

-x = 15+4

x=-19

using equation 1:

y = -3(-19)- 2  

y= 57-2

y= 55

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If g(x)=4x^2-16 we’re shifted 9 united to the right and 1 down, what would the new equation be?
Inessa05 [86]

Shown in the graph

<h2>Explanation:</h2>

Using graph tools we can graph the function:

g(x)=4x^2-16

which is the red graph shown below. As you can see, this is a parabola. The rule for vertical and horizontal shifts is as follows:

Let \ c \ be \ a \ positive \ real \ number. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:

\bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ h(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ h(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ right \ \mathbf{right}: \\ h(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ left \ \mathbf{left}: \\ h(x)=f(x+c)

Therefore, If we shift the red graph 9 units to the right and 1 down, our new function (let's call it h(x)) will be:

h(x)=4\left(x-9\right)^{2}-16-1 \\ \\ Simplifying: \\ \\ h(x)=4\left(x-9\right)^{2}-17

This graph is the blue graph below. Let's verify the transformation taking the vertex of the red graph:

(0,-16)

By translating the 9 units to the right and 1 down the vertex is also translated by the same rule, so:

New \ vertex: \\ \\ (0+9,-16-1) \\ \\ (9,-17)

<h2>Learn more:</h2>

Cubic function: brainly.com/question/13773618#

#LearnWithBrainly

5 0
3 years ago
A fair die is tossed 5 times. Let <img src="https://tex.z-dn.net/?f=%5Cdfrac%7Bm%7D%7Bn%7D" id="TexFormula1" title="\dfrac{m}{n}
Ray Of Light [21]

Answer:

m = 1

Step-by-step explanation:

We can suppose that the number we are looking for is for example 5.

(we can do so because the probability is the same for each number - it'sna fair dice)

For the first toss the probability we have 5 is 1/6 (we have 6 numbers on the dice and number 5 is just one of the possible 6 outcomes).

For the second toss the probability we have 5 is again 1/6.

For the rest of 3 tosses we don'tcare what number we will get( we have our two consecutive 5s), so all of the outcomes for the rest of 3 tosses are good for us (probability is 6/6 = 1)

Threfore, the probability to get two consecutive 5s is 1/6 * 1/6 * 1 * 1 * 1 = 1/36.

We can see that m = 1.

4 0
3 years ago
How do I solve this ​
timurjin [86]

Answer:

4 hours

Step-by-step explanation:

120-72=48

48÷12=4

8 0
3 years ago
Read 2 more answers
HELP PLEASE ASAP!! (10 pts)
Mandarinka [93]

Answer:

is there a question or picture?

8 0
3 years ago
Subtract the equation m-3n/6m3n - m+3n/6m^3n
Sergio039 [100]

Answer:

- n^2m(3 - m^2)/2

3 0
3 years ago
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