Consecutive numbers differ by one. So, if 
is the first, the three numbers are
The sum of the first and third integer is
Is this really a school question or is it just you being weird?
4,200+525(5×12)
4,200+525(60)=
4,200+31,500=35,700
Hello!
First off, please write y2 + y as y^2 + y. The " ^ " symbol denotes exponentiation, whereas y2 is meaningless.
To find the constant term in question, take half of the coefficient of y (that is, take 1/2) and square it. Then we have y2 + y + 1/4.
The constant term in question is 1/4.
