Answer:
x<6/5, x>14/5
Step-by-step explanation:
Steps
$5\left|x-2\right|+4>8$
$\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}$
$5\left|x-2\right|+4-4>8-4$
$\mathrm{Simplify}$
$5\left|x-2\right|>4$
$\mathrm{Divide\:both\:sides\:by\:}5$
$\frac{5\left|x-2\right|}{5}>\frac{4}{5}$
$\mathrm{Simplify}$
$\left|x-2\right|>\frac{4}{5}$
$\mathrm{Apply\:absolute\:rule}:\quad\mathrm{If}\:|u|\:>\:a,\:a>0\:\mathrm{then}\:u\:<\:-a\:\quad\mathrm{or}\quad\:u\:>\:a$
$x-2<-\frac{4}{5}\quad\mathrm{or}\quad\:x-2>\frac{4}{5}$
Show Steps
$x-2<-\frac{4}{5}\quad:\quad x<\frac{6}{5}$
Show Steps
$x-2>\frac{4}{5}\quad:\quad x>\frac{14}{5}$
$\mathrm{Combine\:the\:intervals}$
$x<\frac{6}{5}\quad\mathrm{or}\quad\:x>\frac{14}{5}$
100/95= 1.05. Each question worth 1.1 rounded. You could miss 19 but if you miss 20 you go under 80.
Since y + x = 3, then we could say one of them equals 2 while the other is 1. y - x = 1, then we can say 3 - 1 = 2, so y would be 2 and x would be 1
Answer:28.50
I’m doing a lesson for iready and I had the same question
Pemdas
so do parenthaseese first
work inside then out
(25 times 2)
(50)
now we have
96/42+(50)-15-3=?
start from the begining again of the equation (left) now we do division
96/42=16/7
now we have 16/7+(50)-15-3
start over and do addition
16/7+50=2 and 2/7+50=2+2/7+50=52 and 2/7
subtract
52 and 2/7-15=52+2/7-15=37 +2/7=37 and 2/7
then subtract 3
37 and 2/7-3=37+2/7-3=34+2/7=34 and 2/7
answer is 34 and 2/7
