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bagirrra123 [75]
3 years ago
9

Someone please help me!

Mathematics
2 answers:
Lerok [7]3 years ago
6 0

Answer:

x = -3

Step-by-step explanation:

When you take the cube root of -27, -3 is your answer. To double check, just cube -3 (or -3 x -3 x -3) and you can see you get -27.

Andru [333]3 years ago
6 0

Answer:

<h2>A</h2>

Step-by-step explanation:

x^3=-27

x=cuberootof(-27)

x=cuberootof(-3^3)

x=-3

This is A

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We Fail to reject Null Hypothesis.

Step-by-step explanation:

We are given two dependent random samples;

Population 1   Population 2   d = Population 1 entry-Population 2 entry    d^{2}

      52                       61                                52 - 61 = -9                                 81

      81                        71                                 81 - 71 = 10                                 100

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      67                        62                                67 - 62 = 5                                25

      73                        79                                 73 - 79 = -6                               36

      73                        77                                 73 - 77 = -4                                16

      76                        71                                  76 - 71 = 5                                 25

      83                        85                                 83 - 85 = -2                          <u>     4    </u>

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Now,  Null Hypothesis, H_0 : \mu_1 = \mu_2    or   \mu_d = 0

 Alternate Hypothesis, H_1 : \mu_1 \neq  \mu_2     or   \mu_d \neq  0

The test statistics for paired data is given by;

                   \frac{dbar - \mu_d}{\frac{s_d}{\sqrt{n} } } follows t_n_-_1

 where, dbar = Mean of Population 2 data - Mean of Population 1 data

Mean of Population 1 data = \frac{52+81+72+67+73+73+76+83}{8} = 72.125

Mean of Population 2 data = \frac{61+71+82+62+79+77+71+85}{8} = 73.5

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s_d = Standard Deviation of paired data = \sqrt{\frac{\sum d^{2} - n*(dbar)^{2}  }{n-1} } = \sqrt{\frac{387 - 8*(1.375)^{2}  }{8-1} }

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n = no. of observations = 8

 So, <em>Test Statistics = </em>\frac{1.375 - 0}{\frac{7.3}{\sqrt{8} } }<em> follows </em>t_7<em> </em>

<em>                          = 0.533</em>

Now, if the critical value of t at 7 degree of freedom is less than the test statistics then we will reject null hypothesis.

At 0.01 level of significance, the t table gives a critical value of 3.499. Since our test statistics is less than the critical value we will not reject null hypothesis and conclude that there is no significant difference between the two population means.

                                                                                                       

                                                                                                     

                                                                                                 

                                                                                                       

                                                                                                 

                                                                                                       

                                                                                                   

                                                                                               

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