All categories

3 years ago

I need help please and thank you

Mathematics

1 answer:

STatiana [176]3 years ago

4 0

Answer:

∠A = 45°

Step-by-step explanation:

The sum of angles in a triangle = 180°.

That means in the triangle ABC, ∠A + ∠B + ∠C = 180°.

Given ∠B = 90° and ∠C = 45°.

⇒ ∠A + 90° + 45° = 180°

⇒ ∠A = 180 - 90 - 45

⇒ ∠A = 45° is the required answer.

You might be interested in

HELP? .................................................

joja [24]

Answer:

the last option

Step-by-step explanation:

I'm smart

4 0

3 years ago

Read 2 more answers

Carolina is painting a large pink rectangle on her bedroom wall using chalkboard paint. The rectangle is going to be 1.8 meters

dmitriy555 [2]

Answer:

2.5

Step-by-step explanation:

Usually when you try and find the area you would multiply but you don't have one of the numbers to multiply, so what is the oppisite of multiplication? Divison. You would divide the area by the highth. so it would be 4.5 divided by 1.8. 4.5 divided by 1.8 equals 2.5. And to make sure your answer is correct you would multiply 1.8 times 2.5 wich does equal 4.5. The highth is 1.8, the Length is 2.5, and the are is 4.5

6 0

3 years ago

Which number is 1/10 as great as 0.7?

vichka [17]

I believe the answer is .07

3 0

3 years ago

The polynomial -x^3-x^2+12x represents the volume of a rectangular aqautic tank in cubic feet. the length of the tank is (x+4).

Verizon [17]

Answer:

<h2>a. It should look for 3 linear factors.</h2><h2>b. There are 3 dimensions.</h2><h2>c. x = 1.7</h2><h2>d. Maximum value is 12.597</h2>

Step-by-step explanation:

$-x^{3} - x^{2} + 12 \timesx$ = $-x^{3} - 4 \timesx^{2} + 3 \timesx^{2} +12 \timesx$ = $-(x + 4) \timesx^{2} + 3 \timesx \times(x + 4)$ = $(x + 4) \timesx \times (x + 3)$

Hence the factorized form of the volume of the poly is $(x + 4) \timesx \times (x + 3)$

3 linear factors should needed to be look for.

The 3 dimensions are (x + 4), x, (x + 3).

Let, f(x) = $-x^{3} - x^{2} + 12 \timesx$

Now, $\frac{d f(x)}{dx}$ = $-3 \timesx^{2} -2 \timesx + 12$

Let $f1(x)$ = $-3 \timesx^{2} -2 \timesx + 12$ and $f2(x)$ = $\frac{d f1(x)}{dx}$ = $-3 \timesx -2$

The value will be maximum, if f1(x) = 0 and f2(x) < 0.

$f1(x) = 0$ \\ $3 \timesx^{2} + 2 \timesx -12 = 0$ \\ $x = \frac{- 2 + \sqrt{2^{2} + 4 \times3 \times12} }{2 \times3} , \frac{- 2 - \sqrt{2^{2} + 4 \times3 \times12} }{2 \times3}$

x = 1.69 ≅ 1.7 or x = -2.36 ≅ -2.4

Now f2(1.7) < 0.

At x = 1.7, the volume will be maximum.

The maximum value is f(1.7) = 12.597(approximately)

8 0

3 years ago

Please help me with number 11 and number 12

melomori [17]

For 11. Not all of the y values (outputs) are consistent with the pattern

4 0

3 years ago