The spring constant of the spring if it would compress by 1 m to stop the ore car is 340,350.4 N/m.
<h3>
Potential energy of the car</h3>
The potential energy of the car is calculated as follows;
P.E = mgh
where;
- h is the vertical height of the incline
sin (10) = h/L
h = L x sin(10)
P.E = mgLsin(10)
P.E = 2000 x 9.8 x 50 x sin(10)
P.E = 170,175.21
<h3>Conservation of energy</h3>
The potential energy of the car at the top of the incline will be converted to the elastic potential energy spring at the bottom of the incline.
P.E = U = ¹/₂kx²
k = (2U)/x²
k = (2 x 170,175.2)/(1)²
k = 340,350.4 N/m
Learn more about spring constant here: brainly.com/question/1968517
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Answer:
Gravity Increases - Mass increases, distance decreases
Gravity Decreaes - Mass decreases, distance increases
If you are talking about gravitational potential energy, then the ONLY way to either increase OR decrease it is to raise or lower your height. The higher you are off the ground the greater your PE, the closer you are to the ground, the lower your PE
The wave nature of light, due to the experiment having bright and dark bands corresponding to places where you have constructive and destructive interference.
B) The velocity of a car reduced from 50 km/h to 35 km/h over one minute. <span>B) The velocity of a car reduced from 50 km/h to 35 km/h over one minute. </span>