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2 years ago

Lab: Types of Reactions Assignment: Lab Report

Physics

1 answer:

Thepotemich [5.8K]2 years ago

9 0

The types of chemical reactions are as follows:

Combination reactions
Decomposition reactions
Double decomposition
Thermal dissociation
Redox reactions

<h3>What the are the types of reactions?</h3>

Chemical reactions are changes in which new substances are formed.

The types of chemical reactions are as follows:

Combination reactions - these are reactions in which two or more substances combine to form a single compound
Decomposition reactions - these are reactions in which a larger compound splits into smaller substances
Displacement reactions - these are reactions in which one element or radical replaces another in a compound
Double decomposition - these are reactions in which two substances exchange their radicals to form new compounds.
Thermal dissociation - these reactions involves heating compounds to split them into smaller substances.
Redox reactions - these are reactions in which oxidation and reduction reactions occur simultaneously.

In conclusion, chemical reactions produce new substances.

Learn more about chemical reactions at: brainly.com/question/11231920

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Thats the answer

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3 years ago

Read 2 more answers

Use the values from PRACTICE IT to help you work this exercise. Suppose the same two vehicles are both traveling eastward, the c

Mariulka [41]

Answer:

A. $v_{3}=12.17m/s$

B. $v_{car}=6.3m/s\\v_{truck}=-6.3m/s$

C. ΔK $=-4.13x10^3J$

Explanation:

From the exercise we know that the car and the truck are traveling eastward. I'm going to name the car 1 and the truck 2

$v_{1}=5.79m/s\\m_{1}=102kg\\v_{2}=18.5m/s\\m_{2}=103kg$

A. Since the two vehicles become entangled the final mass is:

$m_{3}=102kg+103kg=205kg$

From linear momentum we got that:

$p_{1}=p_{2}$

$m_{1}v_{1}+m_{2}v_{2}=m_{3}v_{3}$

$v_{3}=\frac{m_{1}v_{1}+m_{2}v_{2}}{m_{3} }=\frac{(102kg)(5.79m/s)+(103kg)(18.5m/s)}{(205kg)}$

$v_{3}=12.17m/s$

B. The change in velocity of both vehicles are:

For the car

$v_{car}=v_{f}-v_{o}=12.17m/s-5.79m/s=6.38m/s$

For the truck

$v_{truck}=12.17m/s-18.5m/s=-6.3m/s$

C. The change in kinetic energy is:

ΔK= $K_{2}-K_{1} =\frac{1}{2}m_{3}v_{3}^{2}-(\frac{1}{2}m_{1}v_{1}^{2}+\frac{1}{2}m_{2}v_{2}^{2})$

ΔK= $\frac{1}{2}(205)(12.17)^{2}-(\frac{1}{2}(102)(5.79)^{2}+\frac{1}{2}(103)(18.5)^{2})=-4.13x10^{3}J$

ΔK $=-4.13x10^{3}J$

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3 years ago

Two children are throwing a ball back-and-forth straight across the back seat of a car. The ball is being thrown 7 mph relative

Evgesh-ka [11]

Answer:

the ball will fly in AX direction, making angle of 8.84° from the motion of the car

Explanation:

Given the data in the question and as illustrated in the diagram below;

Now, Lets assume line AB represent the movement of the car,

AC is the movement of the ball been thrown back and forth in the back seat

Ax is the motion of the ball it flies off the window

so from the diagram, We can see triangle ABC

where AB is 45 mph and AC = 7 mph

and angle ∠CAB = 90°

using SOH CAH TOA

TOA; tanθ = Opposite / Adjacent

tanθ = Opposite / Adjacent

tan( ∠ ABC ) = AC / AB

we substitute

tan( ∠ ABC ) = 7 / 45

tan( ∠ ABC ) = 0.15555

( ∠ ABC ) = tan⁻¹ 0.15555

( ∠ ABC ) = 8.84°

Therefor, angle ( ∠ ABC ) is 8.84°

Meaning angle ( ∠ XAA' ) is also 8.84°

Therefore, the ball will fly in AX direction, making angle of 8.84° from the motion of the car

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3 years ago

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Objects that let in light and blurry images are translucent.

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This term is often confused with transparency. However, they differ because a transparent object lets light through easily and allows you to see clearly through it.

According to the above, objects that allow light to pass through but do not allow clear vision are translucent.

Learn more in: brainly.com/question/10626808

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