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miv72 [106K]
3 years ago
12

In an experiment, James studied the relationship between kinetic energy, mass, and velocity. Four masses were rolled across a sm

ooth surface. If the kinetic energy in Joules remains constant, and the masses change, predict the velocity of the ball with a mass of 40kg
Physics
1 answer:
Alex777 [14]3 years ago
3 0

Answer:

20

Explanation:

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Light waves are electromagnetic waves that travel at 3.00 Light waves are electromagnetic waves that travel 108 m/s. The eye is
svlad2 [7]

(a) 5.45 \cdot 10^{14} Hz

The relationship between frequency and wavelength of an electromagnetic wave is given by

c=f \lambda

where

c=3.00 \cdot 10^8 m/s is the speed of light

f is the frequency

\lambda is the wavelength

In this problem, we are considering light with wavelength of

\lambda=5.50 \cdot 10^{-7} m

Substituting into the equation and re-arranging it, we can find the corresponding frequency:

f=\frac{c}{\lambda}=\frac{3.00 \cdot 10^8 m/s}{5.50 \cdot 10^{-7} m}=5.45 \cdot 10^{14} Hz

(b) 1.83\cdot 10^{-15} s

The period of a wave is equal to the reciprocal of the frequency:

T=\frac{1}{f}

And using f=5.45 \cdot 10^{14} Hz as we found in the previous part, we can find the period of this wave:

T=\frac{1}{5.45 \cdot 10^{14} Hz}=1.83\cdot 10^{-15} s

5 0
3 years ago
A Ferris wheel with 60 spokes has a diameter of 100 m. It makes one rotation every 60 seconds. Find the speed of the passengers
Doss [256]

Answer:

<em>The speed of the passengers is 5.24 m/s</em>

Explanation:

<u>Uniform Circular Motion </u>

It occurs when an object in a circular path travels equal angles in equal times.

The angular speed can be calculated in two different ways:

\displaystyle \omega=\frac{v}{r}

Where:

v = tangential speed

r = radius of the circle described by the rotating object

Also:

\omega=2\pi f

Where:

f = frequency

Since the frequency is calculated when the number of revolutions n and the time t are known:

\displaystyle f=\frac{n}{t}

The Ferris wheel has a diameter of 100 m and makes n=1 rotation in t=60 seconds, thus the frequency is:

\displaystyle f=\frac{1}{60}\ Hz

The angular speed is:

\displaystyle \omega=2\pi \frac{1}{60} =\frac{\pi}{30} \ rad/s

Now we calculate the tangential speed, solving this formula for v:

\displaystyle \omega=\frac{v}{r}

v=\omega . r

The radius is half the diameter, r=100/2=50 m:

\displaystyle v=\frac{\pi}{30} . 50

Calculating:

v = 5.24 m/s

The speed of the passengers is 5.24 m/s

7 0
2 years ago
What is the energy (in J) stored in the 14.0 µF capacitor of a heart defibrillator charged to 6.90 ✕ 103 V?
Eduardwww [97]

Answer:

The energy stored in the capacitor is 333.3 J

Explanation:

Energy stored in a capacitor = CV²/2

C = capacitance = 14 × 10⁻⁶F

V = 6.90 × 10³V

Energy = (14 × 10⁻⁶)(6.90 × 10³)²/2 = 333.27 = 333.3 J

Hope this Helps!!!

6 0
3 years ago
¿Por que una una tapa pequeña de agua purificada se mantiene quieta por más tiempo sobre una rampa, en comparación al tiempo red
shusha [124]

Answer:

Esto sucede principalmente por el movimiento rotacional de las ruedas del carrito.

Como sabemos, existen dos tipos de coeficientes de fricción, el estacionario y el cinético.

En principio, la tapa se mantendrá quieta por que no tendrá la suficiente fuerza como para vencer al coeficiente de fricción estático, por lo que no podrá moverse hasta que esta reciba un pequeño impulso, como puede ser una pequeña corriente de aire. (asumo que la superficie curva de la tapita es la que esta en contacto con la rampa)

(Voy a simplificar el movimiento rotacional, pero creo que es suficiente para explicar la situación)

Ahora, en el carrito, las ruedas están conectadas a un eje.

La fuerza gravitatoria podemos pensarla que esta arriba de este eje, mas o menos en el centro del carrito, y esta fuerza intentara que el carrito baje de la rampa (lo mismo pasa para la tapita), pero a diferencia de la tapita, esta fuerza es aplicada a una distancia dada del eje (o del centro de las rueditas) lo que podemos pensar que funciona como una palanca, amplificando así la fuerza, por lo que esta vez el rozamiento estático podrá detener la superficie de la rueda que esta en contacto con el suelo, pero cuanto el centro de masa se mueva un poco, el punto de contacto entre la rueda y el suelo se moverá, de esta manera aparece lo que llamamos movimiento rotacional (si no hubiera fricción, las ruedas simplemente deslizarían sobre la rampa) que le permite al carrito ignorar en parte al coeficiente de fricción estático.

Otro factor importante, es que las tapitas suelen tener una superficie rugosa y un centro de masa desfazado, lo que no las hace buenas rotadoras.

5 0
2 years ago
Hey can someone send me the answer to this
bagirrra123 [75]

Cars 'A' and 'C' look like they're moving at the same speed.  If their tracks are parallel, then they're also moving with the same velocity.

5 0
3 years ago
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