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Alex73 [517]
3 years ago
14

Molly buys 2 boxes of crackers. Each box has 4 packages of crackers in it. Molly

Mathematics
1 answer:
castortr0y [4]3 years ago
5 0

Answer:

4 x 2 x 10 = 80

Step-by-step explanation:

80 Crackers total divided evenly among the two boxes gives you 40 crackers per box. Next there are 4 packages and 40 crackers in the packages total. So divide 40 by 4. This gives you 10. 10 crackers per package.

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A movie rental company offers a membership plan that costs $10/month and charges $2 to rent each movie. How many movies can a me
Brums [2.3K]

Answer:

See below

Step-by-step explanation:

linear equation: y=2x+10

x=cost per movie rented

10=$10 for the membership

24=2x+10    (24 being total you want to spend)

subtract 10 from each side

14=2x

divide by 2

7=x

He can rent no more than 7 movies if he want to spend $24 or less in the month

8 0
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Step-by-step explanation:

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2 years ago
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I do not get this anyone know???
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8 0
3 years ago
A biologist is studying the elk population in a county park. She starts with only 2 elk and observes that the number of elk trip
DochEvi [55]

Answer:

The expression that represents the population of elk is: \text{elk}(t) = 2*3^t. It'll take 6 years for the population to reach 1,458 individuals.

Step-by-step explanation:

Since the number of elks triples every year and starts at \text{elk}(0) = 2, then after the first year the population will be:

\text{elk}(1) = \text{elk}(0)*3 = 2*3

While on the second year, it'll be:

\text{elk}(2) = \text{elk}(1)*3 = 2*3*3 = 2*3^2

On the third year:

\text{elk}(3) = \text{elk}(2)*3 = 2*3^2*3 = 2*3^3

And so on, therefore the expression that describes the population of elk as the years passes is:

\text{elk}(t) = 2*3^t

If we want to know the number of years until the population reach 1,458 elk, we need to apply this value to the left side of the equation and solve for t.

1458 = 2*3^t\\3^t = \frac{1458}{2}\\3^t = 729\\ln(3^t) = ln(729)\\t*ln(3) = ln(729)\\t = \frac{ln(729)}{ln(3)} = 6

The population will reach 1,458 elk in 6 years.

8 0
3 years ago
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