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3 years ago

13

What are all of the possible classifications for a 3x3 system?

2 answers:

Sever21 [200]3 years ago

5 0

Noor is correct lol I guess that helps

kirill115 [55]3 years ago

3 0

Answer:

Consistent and Dependent

Consistent and Independent

Inconsistent and Independent

Step-by-step explanation:

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A substance has a mass of 10g and a volume of 5cm^3 whats the density

sergiy2304 [10]

Density= Mass/Volume
10/5=2

If I'm correct the density should be 2 cm^3

7 0

3 years ago

How do yall figure out how many people there are in a pie chart if it dont say and all it has is percents

fredd [130]

Change the percent to a decimal and then multiply

8 0

3 years ago

klasskru [66]

Answer:

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$y=0,\:x=6$

Step-by-step explanation:

Considering the system of the equations

$\begin{bmatrix}2x-7y=12\\ -x+15y=-6\end{bmatrix}$

$\mathrm{Isolate}\:x\:\mathrm{for}\:2x-7y=12$

$2x-7y+7y=12+7y$

$2x=12+7y$

Divide both sides by 2

$\frac{2x}{2}=\frac{12}{2}+\frac{7y}{2}$

$x=\frac{12+7y}{2}$

$\mathrm{Subsititute\:}x=\frac{12+7y}{2}$

$\begin{bmatrix}-\frac{12+7y}{2}+15y=-6\end{bmatrix}$

$-\frac{12+7y}{2}+15y=-6$

$\mathrm{Multiply\:both\:sides\:by\:}2$

$-\frac{12+7y}{2}\cdot \:2+15y\cdot \:2=-6\cdot \:2$

$-\left(12+7y\right)+30y=-12$

$-12+23y=-12$

$-12+23y+12=-12+12$

$23y=0$

$\mathrm{Divide\:both\:sides\:by\:}23$

$\frac{23y}{23}=\frac{0}{23}$

$y=0$

$\mathrm{For\:}x=\frac{12+7y}{2}$

$\mathrm{Subsititute\:}y=0$

$x=\frac{12+7\cdot \:0}{2}$

$x=\frac{12}{2}$

$x=6$

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$y=0,\:x=6$

4 0

4 years ago

Damien Smart is trying to decide whether to lease or purchase a new car costing $18,000. If he leases, he’ll have to pay a $600

gizmo_the_mogwai [7]

$the\ lease:\\\\ \$450\cdot36(payments)- \$600(security)=\$16,200-\$600=\$15,600 \\\\ the\ purchase:\\\\down\ payments+payments+sales\ tax- residual\ value= \\\\=\$2,400+\$515\cdot36+\$1,080-\$6,500=\$2.400+\$18,540-\$5420=\\\\=\$15,520\\\\\$15,520$

6 0

3 years ago

Read 2 more answers

Suppose U = {1, 2, 3, 4, 5, 6, 7, 8} is the universal set, and P= {1, 3, 5, 7}. what is P'

katen-ka-za [31]

Answer:

P'= {2, 4, 6 ,8}

Step-by-step explanation:

If you mean by P' - ''complement of P'' or ''U\P'' or ''all elements that does not belong to the P '' or ''¬P'' ( which is all the same) then correct answer is

P'= {2, 4, 6 ,8}.

Good luck!!!

8 0

3 years ago

Read 2 more answers