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krek1111 [17]
2 years ago
11

Find the common ratio

Mathematics
1 answer:
Free_Kalibri [48]2 years ago
8 0
Answer:






31.5






I hope that’s right
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The weather report stated that tomorrow's low temperature will be -3 degrees. What does that statement mean?
Ket [755]

Answer:

It means that the lowest the temperature will get that day is -3 degrees

Step-by-step explanation:

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2 years ago
How long will it take a person to double $2000 at a 6% interest rate, compounded annually?
aleksandr82 [10.1K]
Well you would do 6% times 2000 (.06 *2000) 120

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3 years ago
Marta is making 3 servings of fruit salad.she adds 3/8 cup blueberries for each serving.her measuring cup holds 1/8 cup.how many
quester [9]
To solve this problem you must follow the proccedure shown below:

 1. You have the following information given in the problem above:

 - <span>Marta is making 3 servings of fruit salad.
 - Marta adds 3/8 cups blueberries for each serving.
 - Her measuring cup holds 1/8 cup.

 2. Then, you have:

 1 time----1/8 cup 
         x----3/8 cups

 x=(3/8)/(1/8)

 x= 3x8/1x8
 x=24/8
 x=3 times

 H</span><span>ow many times must Marta measure 1/8 cup of blueberry to have enough for the fruit salad?

 The answer is: 3 times</span>
3 0
3 years ago
Which of these true conditional statements has a false converse?
cestrela7 [59]
Correct answer is A. For example 50/2= 25 which is odd
4 0
3 years ago
The radius of a circle is decreasing at a rate of 6.56.56, point, 5 meters per minute. At a certain instant, the radius is 12121
Ilia_Sergeevich [38]

Answer:

The rate of change of the area of the circle is  approximately -490.09 \ m^2/min.

Step-by-step explanation:

Given:

\frac{dr}{dt} = -6.5 \ m/min

radius r =12 \ m

We need to find the rate of change of the area of the circle at that instant.

Solution:

Now we know that;

Area of the circle is given by π times square of the radius.

framing in equation form we get;

A= \pi r^2

to find the rate of change of the area of the circle at that instant we need to take the derivative on both side.

\frac{dA}{dt}=\frac{d(\pi r^2)}{dt}\\\\\frac{dA}{dt}= 2\pi r \frac{dr}{dt}

Substituting the given values we get;

\frac{dA}{dt}= 2\times \pi \times 12 \times -6.5\\\\\frac{dA}{dt}\approx -490.09 \ m^2/min

Hence The rate of change of the area of the circle is  approximately -490.09 \ m^2/min.

6 0
2 years ago
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