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____ [38]
3 years ago
15

Mr. Barrientos can run 2 ½ miles in 2 hours. How many miles can he run in 6 hours? Show your work.

Mathematics
1 answer:
inysia [295]3 years ago
5 0

Answer:

7 1/2 miles

Step-by-step explanation:

You might be interested in
F(x)=20/4+3e−0.2x
sdas [7]

Answer:

12.6

Step-by-step explanation:

Given the function, F(x)=20/4+3e−0.2x

Where e is an exponential function,

To get f(3), we need to substitute x = 3 into the given function

F(3) = 20/4 + 3e - 0.2(3)

f(3) = 5 + 3e - 0.6

f(3) = 4.4+3e

Substituting the value of e = 2.718

f(3) = 4.4+3(2.718)

f(3) = 12.554

f(3) = 12.6 to the nearest tenth.

8 0
3 years ago
A book of stamps costs $9.80 $ 9 . 80 . The expression 9.8 9 . 8 n represents the price of one stamp. What does the variable n r
andreev551 [17]

Answer: n represents the amount a stamp cost

Step-by-step explanation:


7 0
3 years ago
Please help me I will reward brainlest
nikklg [1K]

C, the sum of the decimals is greater than one, meaning they shade more than one.

4 0
3 years ago
Read 2 more answers
What is 2/5 times 15/16
Flauer [41]
That is 30/80 that reduces down to 3/8
How u get it is 2 times 15 over 5 times 16 then divide 30 and 80 by 10 to get 3/8
6 0
3 years ago
Read 2 more answers
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
3 years ago
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