First, let's find the digit in the tenths place. The quotient of 10 and 2 is 5 because 10/2 = 5. Next, the digit in the hundredths place is the product of 3.5 and 2. 3.5 * 2 = 7. The number in the thousandths place is the sum of the digit in the tenths place and the ten thousandths place, so we have to find the digit in the ten thousandths place first. It says that every number in the code is divisible by the digit in the ten thousands place. The factors of 5 are 1,5 and the factors of 7 are 1,7. The only number that is the same in both is 1, so the last digit must be 1. Knowing that information, we can add the digit in the tenths place (5) to the number in the ten thousandths place (1) to get the third digit (6). Now we place those digits in order: tens (5), hundredths (7), thousandths (6), and ten thousandths (1) to get 5761.
