Answer: g(x)=|x+8|-3
Questions please feel free to ask. Thanks
<h3>Given</h3>
tan(x)²·sin(x) = tan(x)²
<h3>Find</h3>
x on the interval [0, 2π)
<h3>Solution</h3>
Subtract the right side and factor. Then make use of the zero-product rule.
... tan(x)²·sin(x) -tan(x)² = 0
... tan(x)²·(sin(x) -1) = 0
This is an indeterminate form at x = π/2 and undefined at x = 3π/2. We can resolve the indeterminate form by using an identity for tan(x)²:
... tan(x)² = sin(x)²/cos(x)² = sin(x)²/(1 -sin(x)²)
Then our equation becomes
... sin(x)²·(sin(x) -1)/((1 -sin(x))(1 +sin(x))) = 0
... -sin(x)²/(1 +sin(x)) = 0
Now, we know the only solutions are found where sin(x) = 0, at ...
... x ∈ {0, π}
Answer:
-7a+11
Step-by-step explanation:
Using the rules of cosines, the <span>measure of the turn between the second and third legs of the race</span> is given by
Answer:
The correct answer is option C.
The mid point of the line segment.
Step-by-step explanation:
the perpendicular line segment construction twice using paper folding
we have to find the mid point of the given line segment.
We get the midpoint easily when fold the paper correctly
Therefore the correct answer is option C.
The mid point of the line segment.