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Sergio [31]
3 years ago
13

Triangles D E F and P Q R are shown. Given that StartFraction D F Over P R EndFraction = StartFraction F E Over R Q EndFraction

= three-halves, what additional information is needed to prove △DEF ~ △PQR using the SSS similarity theorem? DE ≅ PQ ∠D ≅ ∠P StartFraction D E Over E F EndFraction = three-halves StartFraction D E Over P Q EndFraction = three-halves
Mathematics
2 answers:
geniusboy [140]3 years ago
7 0

Answer:

D. DE/PQ= 3/2

Step-by-step explanation:

2020 edg

alukav5142 [94]3 years ago
3 0

Answer:

The correct option is;

DE/PQ = 3/2 which is StartFraction DE Over PQ Endfraction = three-halves

Step-by-step explanation:

The information given bout the triangles are;

DF/PR = FE/RQ = 3/2

Therefore since the given sides of triangle DEF are 3/2 times the sides of triangle PQR, the given sides of triangle DEF have been scaled 3/2 times to get the given sides of triangle PQR

Therefore, to prove that ΔDEF ~ ΔPQR, the ratio of the third side of triangle DEF, that is DE, to the third side of triangle PQR, which is PQ must be three-halves.

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ziro4ka [17]

Answer:

A.) x-y=2 and x+2y=-2

Step-by-step explanation:

For option A, we have:

x-y=2

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Subtract the first equation from the second, to get:

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Simplify to get:

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Divide both sides by 3 to get:

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The solution is (0.7,-1.3), which is approximately (0.7, -1.4)

By inspection, all the other factors have solutions not close to (0.7, -1.4)

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3 years ago
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Three trucks delivered potatoes to a warehouse. The first truck delivered 5 7/8 tons of potatoes, the second one 6 1/2 tons more
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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