Answer:
The correct option is;
DE/PQ = 3/2 which is StartFraction DE Over PQ Endfraction = three-halves
Step-by-step explanation:
The information given bout the triangles are;
DF/PR = FE/RQ = 3/2
Therefore since the given sides of triangle DEF are 3/2 times the sides of triangle PQR, the given sides of triangle DEF have been scaled 3/2 times to get the given sides of triangle PQR
Therefore, to prove that ΔDEF ~ ΔPQR, the ratio of the third side of triangle DEF, that is DE, to the third side of triangle PQR, which is PQ must be three-halves.
