Question

Triangles D E F and P Q R are shown. Given that StartFraction D F Over P R EndFraction = StartFraction F E Over R Q EndFraction = three-halves, what additional information is needed to prove △DEF ~ △PQR using the SSS similarity theorem? DE ≅ PQ ∠D ≅ ∠P StartFraction D E Over E F EndFraction = three-halves StartFraction D E Over P Q EndFraction = three-halves

Answer 1

Answer:

D. DE/PQ= 3/2

Step-by-step explanation:

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Answer 2

Answer:

The correct option is;

DE/PQ = 3/2 which is StartFraction DE Over PQ Endfraction = three-halves

Step-by-step explanation:

The information given bout the triangles are;

DF/PR = FE/RQ = 3/2

Therefore since the given sides of triangle DEF are 3/2 times the sides of triangle PQR, the given sides of triangle DEF have been scaled 3/2 times to get the given sides of triangle PQR

Therefore, to prove that ΔDEF ~ ΔPQR, the ratio of the third side of triangle DEF, that is DE, to the third side of triangle PQR, which is PQ must be three-halves.