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iVinArrow [24]
3 years ago
5

Help me help me help me

Mathematics
1 answer:
polet [3.4K]3 years ago
6 0

Answer:

D 28

Step-by-step explanation:

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Answer and show work.<br><br> 1.) 9 - t = 3 (t -5) <br><br> 2.) 5 (5y + 1) =10y - 25
AlladinOne [14]

Answer:

1. 6

2. 2

Step-by-step explanation:

1. 9-t=3(t-5)

9-t=3t-15

+t +t

9=4t-15

+15 +15

<u>24</u>=<u>4t</u>

4 4

6=t

2.5(5y+1)=10y-25

25y+5=10y-25

+25 +25

25y+30=10y

-25 -25

<u>30</u>=<u>-15y</u>

15 15

2=y

6 0
3 years ago
This question shows the power of conserved quantities. consider a particle in a smooth monotonic attractive central potential v
Anit [1.1K]
Somebody answer please 
7 0
3 years ago
Under his cell phone plan, Owen pays a flat cost of $67.50 per month and $4 per gigabyte. He wants to keep his bill at $71.90 pe
Agata [3.3K]

Answer:

1.1 gigabytes

Step-by-step explanation:

Let us represent:

The number of gigabytes = g

Under his cell phone plan, Owen pays a flat cost of $67.50 per month and $4 per gigabyte. He wants to keep his bill at $71.90 per month.

The Equation is given as:

$71.90 = $67.50 + $4 × g

71.90 = 67.50 + 4g

71.90 - 67.50 = 4g

4.4 = 4g

x = 4.4/4

x = 1.1 gigabytes

Therefore, the number of gigabytes of data Owen can use while staying within his budget is 1.1 gigabytes

8 0
3 years ago
Read 2 more answers
Alyssa can run 0.75 mile in 35 seconds. About how long will it take her to run 7 miles?
Liono4ka [1.6K]

Answer:

327 Seconds

Step-by-step explanation:

7/.75=28/3

28/3 X 35 = 327 Seconds

8 0
3 years ago
Read 2 more answers
A printer has a contract to print 100,000 posters for a political candidate. He can run the posters by using any number of plate
yulyashka [42]

Answer:

25

Step-by-step explanation:

From the given information;

Numbers of posters that can be printed in an hour = no of impression/hour × no of plate utilized in each impression.

= 1000x

Thus, the required number of hours it will take can be computed as:

\implies \dfrac{100000}{1000x} \\ \\ =\dfrac{100}{x}

cost per hour = 125

If each plate costs $20 to make, then the total number of plate will equal to 40x

∴

The total cost can be computed as:

C(x) = (\dfrac{100}{x}) \times 125 + 20 x --- (1)

C'(x) = (-\dfrac{12500}{x^2})  + 20  --- (2)

At C'(x) = 0

\dfrac{12500}{x^2} = 20

\dfrac{12500}{20} = x^2

x^2= 625

x = \sqrt{625}

x = 25

C'' (x) = -12500 \times \dfrac{-2}{x^3} +0

C'' (x) = \dfrac{25000}{x^3}

where; x = 25

C'' (x) = \dfrac{25000}{25^3}

C''(x) = 1.6

Thus, at x = 25, C'' > 0

As such, to minimize the cost, the printer needs to make 25 metal plates.

4 0
3 years ago
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