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3 years ago

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A card chosen at random from a deck of 52 cards. There are 4 queens and 4 kings in a deck of playing cards. What is the probabil

ity it is a queen or a king?

1 answer:

Romashka-Z-Leto [24]3 years ago

7 0

.15 or 15% you have (4/52)+(4/54) for queens and kings therefore that’s your probability

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Please help quick what is the answer thank you

notka56 [123]

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=> for m we need to find the slope of line which is y2 - y1/ x2 - x1
=> 7-1/ -1-1 = 6/-2 = -3
and as we can in the diagram the y intercept is 4
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The function y = x + 7 is graphed in the coordinate plane. Which point will not be on the line?

kondor19780726 [428]

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(x, y)

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AlexFokin [52]

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Rationalize the denominator of \frac{1 \sqrt{3}}{1-\sqrt{3}}. When you write your answer in the form A B\sqrt{C}, where A, B, an

kobusy [5.1K]

Answer:

The value of ABC is 6.

Step-by-step explanation:

Consider the expression

$\frac{1+\sqrt{3}}{1-\sqrt{3}}$

Rationalize the denominator.

$\frac{1+\sqrt{3}}{1-\sqrt{3}}\times \frac{1+\sqrt{3}}{1+\sqrt{3}}$

$\frac{(1+\sqrt{3})^2}{1^2-(\sqrt{3})^2}$

$\frac{1^2+(\sqrt{3})^2+2\sqrt{3}}{1-3}$

$\frac{1+3+2\sqrt{3}}{-2}$

$\frac{4+2\sqrt{3}}{-2}$

$\frac{4}{-2}+\frac{2\sqrt{3}}{-2}$

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The answer in the form

$A+B\sqrt{C}$ .... (2)

On comparing (1) and (2), we get

$A=-2,B=-1,C=3$

We need to find the value of ABC.

$ABC=(-2)(-1)(3)=6$

Therefore the value of ABC is 6.

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3 years ago