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stealth61 [152]
2 years ago
11

Solve the followingequation and check your answer​

Mathematics
2 answers:
suter [353]2 years ago
7 0

Answer:

use the app socratic to find the answer

Travka [436]2 years ago
5 0

Answer:

8/9

Step-by-step explanation:

5a-3=a/2+1

2(5a-3)=a+2

10a-6=a+2

10-a=6+2

9a/9=8/9

a=8/9

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Solve for x: 6x + 1 over 4 (4x + 8) > 12
sukhopar [10]

Answer:

A. x>\frac{10}{7}.

Step-by-step explanation:

We have been given an inequality 6x+\frac{1}{4}(4x+8)>12. We are asked to solve the given inequality for x.

Using distributive property, we will get:

6x+\frac{1}{4}*4x+\frac{1}{4}*8>12

6x+x+2>12

7x+2>12

Subtract 2 from both sides:

7x+2-2>12-2

7x>10

Divide both sides by 7:

\frac{7x}{7}>\frac{10}{7}

x>\frac{10}{7}

Therefore, option A is the correct choice.

3 0
2 years ago
Which is the graph for the equation y=-3x + 4?
Ivahew [28]

Answer:

its look like this

Step-by-step explanation:

3 0
3 years ago
Simplify the following surd expressions<br> a) 7/3 - 2/3 + V3 - 3V3
Nata [24]

Answer:

\frac{7}{3}-\frac{2}{3}+\sqrt{3}-3\sqrt{3}=\frac{5}{3}-2\sqrt{3}    

Step-by-step explanation:

Given the expression

\frac{7}{3}\:-\:\frac{2}{3}\:+\:v^3\:-\:3v^3

solving the expression

\frac{7}{3}\:-\:\frac{2}{3}\:+\:\sqrt{3}-3\sqrt{3}

combine the fractions i.e \frac{7}{3}-\frac{2}{3}=\frac{5}{3}

\frac{7}{3}\:-\:\frac{2}{3}\:+\:\sqrt{3}-3\sqrt{3}=\frac{5}{3}+\sqrt{3}-3\sqrt{3}

add similar elements  i.e \sqrt{3}-3\sqrt{3}=-2\sqrt{3}

                                 =\frac{5}{3}-2\sqrt{3}      

Thus,

\frac{7}{3}-\frac{2}{3}+\sqrt{3}-3\sqrt{3}=\frac{5}{3}-2\sqrt{3}                        

4 0
2 years ago
Suppose that y is directly proportional to x, and y = 150 when x = 15. What is the constant of proportionality?
galina1969 [7]

Answer:  The required constant of proportionality is 10.

Step-by-step explanation:  Given that y is directly proportional to x, and y = 150 when x = 15.

We are to find the constant of proportionality.

According to the given information, we can write

y\propto x\\\\\Rightarrow y=kx~~~~~~~~~~~~~~~~[\textup{where k is the constsnt of propotionality}].

When y = 150 and x = 15, we get from the above equation that

y=kx\\\\\Rightarrow 150=k\times15\\\\\Rightarrow k=\dfrac{150}{15}\\\\\Rightarrow k=10.

Thus, the required constant of proportionality is 10.

3 0
2 years ago
Name 2 pair of interior angles
ivanzaharov [21]
Adjacent interior angels
8 0
3 years ago
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