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Sloan [31]
3 years ago
13

Find the value of the expression 9.16 + k for k = 9.

Mathematics
1 answer:
maria [59]3 years ago
6 0

Answer:

18.16

Step-by-step explanation:

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PLEASE HELP THANK YOU, WHO EVER ANSWERS ILL GIVE BRAINLIEST PLEASE DO IT RIGHT THOUGH
Alborosie

Answer:

its a bit blurry i cant see

Step-by-step explanation:

3 0
3 years ago
A girl scout sells 3 boxes of cookies during week 1. She has a goal to sell twice as many cookies each week as she did the week
snow_lady [41]

Answer

93 boxes

Step-by-step explanation:

Week one= 3 boxes

Week two= 2×3=6 boxes

Week three= 2×6=12 boxes

Week four= 2×12=24 boxes

Week five= 2×24=48 boxes

Total number of boxes sold is the sum for boxes sold in week 1,2,3,4 and 5

T=3+6+12+24+48=93

8 0
3 years ago
Read 2 more answers
Two adjacent angles whose non common sides are opposite rays are
Arte-miy333 [17]
<span>Two adjacent angles whose non common sides are opposite rays are a linear pair. </span>
6 0
3 years ago
What are all the values of x, for which the square of x is equal to the value of x increased by 2?
Sedbober [7]
=±22
x
=
±
2
x
2


Using the fact that 2=ln2
2
=
e
ln
⁡
2
:

=±ln22
x
=
±
e
x
ln
⁡
2
2


−ln22=±1
x
e
−
x
ln
⁡
2
2
=
±
1


−ln22−ln22=∓ln22
−
x
ln
⁡
2
2
e
−
x
ln
⁡
2
2
=
∓
ln
⁡
2
2


Here we can apply a function known as the Lambert W function. If =
x
e
x
=
a
, then =()
x
=
W
(
a
)
.

−ln22=(∓ln22)
−
x
ln
⁡
2
2
=
W
(
∓
ln
⁡
2
2
)


=−2(∓ln22)ln2
x
=
−
2
W
(
∓
ln
⁡
2
2
)
ln
⁡
2


For negative values of
x
, ()
W
(
x
)
has 2 real solutions for −−1<<0
−
e
−
1
<
x
<
0
.

−ln22
−
ln
⁡
2
2
satisfies that condition, so we have 3 real solutions overall. One real solution for the positive input, and 2 real solutions for the negative input.

I used python to calculate the values. The dps property is the level of decimal precision, because the mpmath library does arbitrary precision math. For the 3rd output line, the -1 parameter gives us the second real solution for small negative inputs. If you are interested in complex solutions, you can change that second parameter to other integer values. 0 is the default number for that parameter.
8 0
3 years ago
Assume a class has 17 members.
Helga [31]
A) 4080
B) 6188

A is a permutation, since order would matter:
P(17, 3)=\frac{17!}{(17-3)!}=\frac{17!}{14!}=4080

B is a combination, since order does not matter:
_{17}C_5=\frac{17!}{5!12!}=6188
6 0
3 years ago
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