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NISA [10]
3 years ago
10

Question 2 (1 point)

Mathematics
1 answer:
Montano1993 [528]3 years ago
3 0

Answer:

The correct option is;

C. She should go back and remeasure all of her specimens again to find the error. If she can't do this, she should eliminate the outlier from the analysis, because this is an error in recording

Step-by-step explanation:

In order to minimize error in measurement, some valuable steps includes;

1) Perform a double check on all measurements to ensure that the measurements recorded are accurate

2) Ensure proper training before taking measurements

3) Measurements should only be taken under controlled conditions

4) Separate the entire population into smaller groups for proper recording

5) Have a second observer double check the records

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I think it's 11:4 so D?
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Compare and contrast the solution of a-3=15 and a-3 is greater than or equal to 15.
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2 years ago
F(x)=2x^2-3x+7 evaluate f(-2)
Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let  p(x)=kpx+dp  and  q(x)=kqx+dq  than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7  

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7  

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)  

So you want:

−2kpk2q=0  

and

kpkq=−1  

and

2kpd2p−3kpdq+7=0  

Now I amfraid this doesn’t work as  −2kpk2q=0  that either  kp  or  kq  is zero but than their product can’t be anything but  0  not  −1 .

Answer: there are no such linear functions.

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ahrayia [7]

Answer:

(4,2)

Step-by-step explanation:

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5(4)-4(2)=12

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3 years ago
Read 2 more answers
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