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4 years ago

What are the first 2 steps in solving a radical equation

1 answer:

5 0

1-) isolate the radical symbol on one side of the equation

2-) square both sides of the equation to eliminate the radical symbol

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When 59,527 is divided by 23, the quotient is 2,588 R ___.

Andru [333]

Here, the picture below

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3 years ago

The parent function f(x) = x2 is translated such that the function g(x) = –x2 + 6x – 5 represents the new function. What is true

kkurt [141]

Answer:

1. Translation 3 units to the right;

2. Reflection across the x-axis;

3. Translation 4 units up.

Step-by-step explanation:

First, rewrite the function $g(x)$ in following way:

$g(x)=-x^2+6x-5=-(x^2-6x)-5=-(x^2-6x+9-9)-5=-(x-3)^2+9-5=-(x-3)^2+4.$

Apply such transformations:

1. Translate the graph of the parent function $f(x)$ 3 units to the right to get the graph of the function $f_1(x)=(x-3)^2.$

2. Reflect the graph of the function $f_1(x)$ across the x-axis to get the graph of the function $f_2(x)=-(x-3)^2.$

3. Translate the graph of the function $f_2(x)$ 4 units up to get the graph of the function $g(x)=-(x-3)^2+4.$

8 0

4 years ago

Read 2 more answers

If x is an integer, then is -x positive?

Andrei [34K]

Answer:

If x is an integer, then for values of x ≤ 0 would -x be positive.

General Formulas and Concepts:

Integers

Step-by-step explanation:

We know that integers comprise of the number line from -∞ to ∞. We can have numbers like -3, -2, -1, 0, 1, 2 ,3.

If we say that x is an integer, and that -x must be positive, then that means the integer x must be negative, because a negative times a negative is a positive.

∴ x can only be negative integers, thus giving us x ≤ 0.

3 0

3 years ago

The equation below describes a circle. What are the coordinates of the center

Rzqust [24]

The equation of a circle: $(x-h)^2 + (y-k)^2 = r^2 \ Where \ (h, k) \ the \ origin \ of \ the \ circle\\(x-6)^2 + (y+5)^2 = 152 => C(6, -5)$

3 0

3 years ago

Read 2 more answers

What is (Alpha + ß )^2 = ??

tensa zangetsu [6.8K]

(α + β)²

= (α + β)(α + β)

= α(α + β) + β(α + β)

= α² + αβ + αβ + β²

= α² + 2αβ + β²

6 0

4 years ago