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3 years ago

Two consecutive integers are such that 3 times the larger exceeds twice the smaller by 34. find the integers.

Mathematics

2 answers:

julsineya [31]3 years ago

7 0

x - a smaller number

(x+1) - a larger number

3(x+1) - 2x = 34

3x + 3 - 2x = 34

x= 31

(x+1) = 32

rodikova [14]3 years ago

5 0

Answer: larger = 32 and smaller = 31

Step-by-step explanation:

let's call the smaller x. The larger must be x+1, because they are consecutives.

3 times the larger exceeds twice the smaller by 34, so:

3(x+1) = 2x+34

3x+3=2x+34

3x-2x=34-3

x=31

x+1 = 32

Checking:

3.32 = 92

3.31+34 = 96 ok

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To simplify the given expression.

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