The position of an object moving vertically along a line is given by the function s(t)=−16t2

Mathematics

1 answer:

kumpel [21]3 years ago

7 0

$\\$Velocity = $\frac{Displacement}{total time}$;$

$s(t) = -16t^2+128t\\\\$a) \\$Vel_1 = \frac{s(4) - s(1)}{4 - 1} = \frac{144}{3} = 48\\$b)\\$Vel_2 = \frac{s(3) - s(1)}{3-1} = \frac{128}{2} = 64\\$c)\\$Vel_3 = \frac{s(2) - s(1)}{2-1} = \frac{80}{1} = 80\\$d)\\$Vel_4 = \frac{s(1+h) - s(1)}{1+h-1} = \frac{-4h(h+6)}{h} = -4h - 24$

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