3 years ago

Answer these please. Thank you.

Mathematics

1 answer:

tiny-mole [99]3 years ago

3 0

A spinner divided into 2 congruent sectors, spun 7 times.

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What line is perpendicular to y= 2x - 4

kolezko [41]

In Perpendicular product of slope is -1 so slope of y=2x-4 is 2 and 2*m=-1 m= -1/2 so y= -1/2x -4

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What is 3.75 written in word form

lord [1]

Three and seventy-five hundredths.

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disa [49]

1 and 31

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Yuri thinks that 3/4 is a root of the following function. q(x) = 6x3 + 19x2 – 15x – 28 Explain to Yuri why 3/4 cannot be a root.

k0ka [10]

Answer:

Yuri is not correct.

Step-by-step explanation:

Given expression is q(x) = 6x³ + 19x² - 15x - 28

If 'a' is a root of the given function, then by substituting x = a in the expression, q(a) = 0

Similarly, for x = $\frac{3}{4}$ ,

$q(\frac{3}{4})=6(\frac{3}{4})^3+19(\frac{3}{4})^2-15(\frac{3}{4})-28$

= $6(\frac{27}{64})+19(\frac{9}{16})-15(\frac{3}{4})-28$

= $(\frac{162}{64})+(\frac{171}{16})-(\frac{45}{4})-28$

= $(\frac{162}{64})+(\frac{684}{64})-(\frac{720}{64})-\frac{1792}{64}$

= $-\frac{1666}{64}$

= $-\frac{833}{32}$ ≠ 0

Therefore, Yuri is not correct. x = $\frac{3}{4}$ can not be a root of the given expression.

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PLEASE HELP ME WITH THIS I WILL GIVE BRAINLIEST

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