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trasher [3.6K]
2 years ago
10

2. (8 points) If you have n gold coins with one a fake that you know is slightly lighter, how many weighings on the pan balance

will you need to ensure that you can find the fake? Explain your answer.
Mathematics
1 answer:
pogonyaev2 years ago
5 0

Answer:

Only 1 Time

Step-by-step explanation:

Since you know that one coin is fake and that the coin is lighter than the rest , then you would only need to weigh all the coins together 1 time to ensure that you will find the fake coin. We can determine this by doing the following.

<u>Example:</u>

Lets say we have 100 coins that weigh 1 gr each. Meaning that the total weight of the 100 coins would be (100coins*1gr = 100gr) <em><u>IF</u></em> there are no fake coins in the batch.

Knowing this we can weigh the entire batch 1 time and if the total weight is less than 100gr we know that the fake coin is in that batch.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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Answer:

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Step-by-step explanation:

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If the interest rate is 7%, how many years will it take for your bank balance to double from $1,000 to $2,000?Enter the followin
svlad2 [7]

Answer:

It will take 14.29 years for your bank balance to double from $1,000 to $2,000.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

E = P*I*t

In which E are the earnings, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

After t years, the total amount of money is:

T = E + P.

If the interest rate is 7%, how many years will it take for your bank balance to double from $1,000 to $2,000?

We have that P = 1000, I = 0.07

We want to find t when E = 1000, so T = P + E = 2000.

E = P*I*t

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Prove that:
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Answer:

<u>Identities used:</u>

  • <em>1/cosθ = secθ</em>
  • <em>1/sinθ = cosecθ</em>
  • <em>sinθ/cosθ = tanθ</em>
  • <em>cosθ/sinθ = cotθ</em>
  • <em>sin²θ + cos²θ = 1</em>
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  • (1 - sinθ)² / (1 - sin²θ) =
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<u>Square root of it is:</u>

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