Answer:
<h2>
100, -50, 25, -12.5, 6.25, -3.125, 1.5625, -0.78125</h2>
Step-by-step explanation:
Each term is being multiplied by <u>-0.5</u>
How did I know?
Divide the second term by the first.
-50 divided by 100 = -1/2
Find the last four terms.
-12.5 x -1/2 =<em> </em><u><em>6.25</em></u>
6.25 x -1/2 = <u><em>-3.125</em></u>
-3.125 x -1/2 = <u>1.5625</u>
1.5625 x -1/2 =<em><u> -0.78125</u></em>
Answer:
0.0008
Step-by-step explanation:
The formula for a hypergeometric probability is

where N is the population, A is the number of objects of type A, B is the number of objects of type B, n is the sample size and x is the number of successes.
In this problem, N is 13. A is 5, since there are 5 objects drawn, and B is 8, since there are 8 remaining objects.
The sample size, n, is 5, and x is 5:

Answer: 10.71
Step-by-step explanation:
1 pound on earth = 1.19 pounds on Neptune
9 pounds on earth means 9 x 1.19 = 10.71
The speed of the object is 12121 m per week.
What does it mean to do speed?
- “Speed” is a street name for various stimulant drugs that teens, young adults and others use to feel more alert and focused, and in some cases, to feel high.
- Some people also use various forms of speed to reduce their appetite. Types of speed include: Amphetamines (used to treat ADHD, narcolepsy, and depression)
The object is moving at a speed of 2 centimeters every 7 seconds.
We need to find the speed in m per week.
2 cm = 0.02 m
1 week = 604800 s
7 s = 
Speed = distance/time
So,


or v = 12121 m/ week
So, the speed of the object is 12121 m per week.
Learn more about speed
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Let

Integrate by parts, taking
<em>u</em> = <em>x</em> ==> d<em>u</em> = d<em>x</em>
d<em>v</em> = sin<em>ᵐ </em>(<em>x</em>) d<em>x</em> ==> <em>v</em> = ∫ sin<em>ᵐ </em>(<em>x</em>) d<em>x</em>
so that

There is a well-known power reduction formula for this integral. If you want to derive it for yourself, consider the cases where <em>m</em> is even or where <em>m</em> is odd.
If <em>m</em> is even, then <em>m</em> = 2<em>k</em> for some integer <em>k</em>, and we have

Expand the binomial, then use the half-angle identity

as needed. The resulting integral can get messy for large <em>m</em> (or <em>k</em>).
If <em>m</em> is odd, then <em>m</em> = 2<em>k</em> + 1 for some integer <em>k</em>, and so

and then substitute <em>u</em> = cos(<em>x</em>) and d<em>u</em> = -sin(<em>x</em>) d<em>x</em>, so that

Expand the binomial, and so on.