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3 years ago

In the diagram ,M//N . Identify all of the angles that are congruent to 2

Mathematics

2 answers:

jekas [21]3 years ago

6 0

Angles 4, 6 and 8 because angles 2 and 4 are opposite each other. Angles 2 and 6 are equal and angle 8 is opposite to angle 6 therefor they are equal. Opposite angles are equal.

ZanzabumX [31]3 years ago

5 0

Answer:

Angles 4, 6 and 8.

Step-by-step explanation:

Let α and β be two angles, these will be congruent angles if they have exactly the same measure, that is, α = β.

A line that cuts two parallels forms congruent angles.

When two intercept lines form 4 angles. Those that are opposite to each other are vertical angles, these are always congruent.

In the diagram you can see that the angles congruent to 2 are: 4, 6 and 8.

Angle 4 is opposite to the angle 2, therefore it is congruent.

Angle 6 has the same measure of angle 2 because the lines m and n are parallel.

Angle 8 is opposite angle 6, so it is congruent to angle 2 which is equal to angle.

Hope this helps!

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Can someone help me with this problem please? Thank you!

Olenka [21]

Answer:

Step-by-step explanation:

since the Pythagorean theorem is

$c=$ √ $a^2+b^2$

b is the bottom line (48)

a is the right line (14)

c is the top line (c)

plug that in

$c =$ √ $14^2 + 48^2$

then do the exponets

$14^2$ = 14 * 14 = 196

$48^2$ = 48 * 48 = 2304

then add them together

196 + 2304 = 2500

$c =$ √2500

the sqrt of 2500 is 50 (50 * 50 = 2500)

c = 50

your answer is 50

hope this helps:)

6 0

2 years ago

Read 2 more answers

Michael can buy 4 sandwiches and 3 cups of coffee for $23.75. Amy can buy 2 sandwhiches and 5 cups of coffee for $19.75 how much

Kobotan [32]

Answer: The cost of one sandwich is $4.25 and the cost of one cup of coffee is $2.25.

Step-by-step explanation:

Let x be the cost of one sandwich and y be the cost of one cup of coffee.

By considering the given situation, we have the following equations :-

$4x+3y=23.75.................(1)\\\\2x+5y=19.75................(2)$

Multiply 2 on both sides of equation (2) , we get

$4x+10y=39.5................(3)$

Subtract equation (1) from equation (3), we get

$7y=15.75\\\\\Rightarrow\ y=\dfrac{15.75}{7}=2.25$

Put value of y in (1), we get

$4x+3(2.25)=23.75\\\\\Rightarrow\ 4x+6.75=23.75\\\\\Rightarrow\ 4x =17\\\\\Rightarrow\ x=4.25$

Hence, the cost of one sandwich is $4.25 and the cost of one cup of coffee is $2.25.

8 0

2 years ago

the three largest islands in canada are all north of the arctic cirlce. baffin island has about 2 1/3 times the area of victoria

nikklg [1K]

Maybe you should work on starting you're sentences.

3 0

3 years ago

Select the correct answer. Given: AD = CF BC = DE Prove: AB = EF Statement Reason 1. AD = CF given 2. AD = AB + BC + CD CF = CD

madreJ [45]

Answer:

Step-by-step explanation: The answer is D- Substitution Property of Equality. I just did the test and it was right.

8 0

3 years ago

Read 2 more answers

The nth term of a sequence is 3n^2- 1

Thepotemich [5.8K]

Answer: The number that belongs to both sequences is 26.

Step-by-step explanation:

We have two sequences, let's call one as A and the other as B.

The n-th term of sequence A is written as:

aₙ = 3*n^2 - 1

the nth term of sequence B is written as:

bₙ = 30 - n^2

We want to find a term that belongs to both sequences, (it can be for different integers, we can use n for sequence A and x for sequence B)

Then we want to find:

aₙ = bₓ

where n and x are integer numbers.

Then we will heave:

3*n^2 - 1 = 30 - x^2

To find the pair, we could isolate one of the variables, then input different integers in the other variable and see if the outcome is also an integer.

Let's isolate n.

3*n^2 = 30 - x^2 + 1

3*n^2 = 31 - x^2

n^2 = (31 - x^2)/3

n = √( (31 - x^2)/3)

Now let's input different values for x, and see if the outcome is also an integer, notice that x is in a negative term inside a square root, then we have only a few values of x such that the equation can be true.

Then let's start with x = 1.

n(1) = √( (31 - 1^2)/3) = √(30/3) = √10

We know that √10 is not an integer.

now with x = 2,

n(2) = √( (31 - 2^2)/3) = √( (31 - 4)/3) = √(27/3) = √9 = 3

then if x = 2, we have n = 3.

Both of them are integers, then we get:

a₂ = 3*(3)^2 - 1 = 27 - 1 = 26

b₃ = 30 - 2^2 = 30 - 4 = 26

The number that belongs to both sequences is 26.

5 0

2 years ago