(f * g)
(4x^2 + 12)(x - 1) = x(4x^2 + 12) - 1(4x^2 + 12) = 4x^3 + 12x - 4x^2 - 12 =
4x^3 - 4x^2 + 12x - 12
(f*g)(3) = 4(3^3) - 4(3^2) + 12(3) - 12 = 4(27) -4(9) + 36 - 12 =
108 - 36 + 36 - 12 =
96 <===
If -0.14 is changed to 2, the graph would become a positive graph, or it would be steeper, because it has a positive slope
The equation of the graph is given as:

The above equation is a linear equation, which is represented as:

Where m represents the slope of the linear equation.
By comparison, we have:

i.e. the slope of the equation
is -0.14
When -0.14 is replaced with 2, the equation becomes

And the slope of the new equation
is

2 is greater than -0.14, and 2 is positive.
This means that the graph would become a positive graph, or it would be steeper, because it has a positive slope
Read more linear equations at:
brainly.com/question/19045223
Answer:
I don't know if this is correct but I got this. y=1/4,y2=4