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2 years ago

6

Make a t Rectangle drawing to represent each excediste. Then find the product.

1 answer:

Trava [24]2 years ago

4 0

I need the actual problem to answer this question

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Need help Asap thank you in advance

julia-pushkina [17]

Answer:

$12x^4-20x^2+32x=4x(3x^3-5x+8)$

Step-by-step explanation:

<u>Common Factors</u>

An algebraic expression that is formed by sums or subtractions of terms can be factored provided there are numeric or variable common factors in all the terms.

The following expression

$Z=12x^4-20x^2+32x$

Can be factored in the constants and in the variable x.

1. To find the common factor of the variable, we must locate if the variable is present in all terms. If so, we take the common factor as the variable with an exponent which is the lowest of all the exponents found throughout the different terms. In this case, the lowest exponent is x (exponent 1).

2. To find the common factors of the constants, we take all the coefficients:

12 - 20 - 32

and find the greatest common divisor of them, i.e. the greatest number all the given numbers can be divided by. This number is 4, since 12/4=3, 20/4=5 and 32/4=8

3. The factored expression is

$Z=12x^4-20x^2+32x=4x(3x^3-5x+8)$

$\boxed{12x^4-20x^2+32x=4x(3x^3-5x+8)}$

3 0

3 years ago

(multiple choice) plz help

zhenek [66]

Answer:option 3

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Hurry i need asap thx

soldier1979 [14.2K]

Answer the Answer is -8

3 0

2 years ago

Read 2 more answers

A quadratic relation has zeros at 3 and –5. The parabola goes through the point (2, –14). What is the equation of the parabola i

olasank [31]

Answer:

$\displaystyle 2 {x}^{2} + 4x - 30 = 0$

Step-by-step explanation:

we are given the zeros and a point where it goes through of a quadratic equation

remember that when the roots are given then the function should be

$\displaystyle \: y = a(x - x_{1})(x - x_{2})$

where a is the leading coefficient and x1 and x2 are the roots

substitute:

$\displaystyle y = a(x - (3))(x - ( - 5))$

simplify:

$\displaystyle y = a(x - 3)(x + 5)$

now the given point tells us that when x is 2 y is -14 therefore by using the point we can figure out a

substitute:

$\displaystyle a(2 - 3)(2 + 5) = - 14$

simplify parentheses:

$\displaystyle a( - 1)(7) = - 14$

simplify multiplication:

$\displaystyle - 7a = - 14$

divide both sides by -7:

$\displaystyle a = 2$

altogether substitute:

$\displaystyle y = 2(x - 3)(x + 5)$

since it want the equation y should be

$\displaystyle 2(x - 3)(x + 5) = 0$

recall quadratic equation standard form:

$\displaystyle {ax}^{2} + bx + c = 0$

so simplify parentheses:

$\displaystyle 2( {x}^{2} + 2x - 15 ) = 0$

distribute:

$\displaystyle 2 {x}^{2} + 4x - 30 = 0$

hence,

the equation of the parabola in standard form is <u>2</u><u>x</u><u>²</u><u>+</u><u>4</u><u>x</u><u>-</u><u>3</u><u>0</u><u>=</u><u>0</u>

8 0

2 years ago

Jo is thinking of a number. Four less than 9 the number is 176 . Find Jo’s number.

Sphinxa [80]

Answer: x = 20

Step-by-step explanation:

Let x represent the number

9x - 4 = 176

9x = 180

x = 20

checking our answer

9*20-4 = 180- 4 = 176

7 0

2 years ago

Read 2 more answers