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larisa86 [58]
3 years ago
13

Geometry: Area... triangles and squares

Mathematics
1 answer:
vodka [1.7K]3 years ago
5 0

Answer:

The answer is A

Step-by-step explanation:

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Please help I am confused.
nignag [31]

Answer:

9 cm, C

11 cm, B

14 cm A

Step-by-step explanation:

7 0
2 years ago
The graph of y = 4 – is shown.
Ratling [72]
Rather than try to select the correct answer without doing work, I'd rather do the work first and the matching later.

Given y = 4 - x, or    y = 4 - 1x,

1) the y-intercept is (0,4).
2) this being a linear function, it has neither maximum nor minimum.
3) the x-intercept is found by letting y = 0 and solving for x:  0 = 4 - x; x - 4.  The x-intercept is (4,0).

Which of the given statements is true?
7 0
3 years ago
If the actor is to the audience’s right the actor is _______.
kati45 [8]
I think the answer is stage left because if you flip your view point, you'll get stage left. 
Hopefully that helped! :) 
7 0
3 years ago
What are the coordinates of point B on \overline{AC} such that AB = 1/2 BC
marta [7]

Answer:

C. B(x,y) = \left(3,-\frac{16}{3} \right)

Step-by-step explanation:

Let A(x,y) = (6,-7), B(x,y) = (x,y) and C(x,y) = (-3,-2). From statement we know that AB = \frac{1}{2}\cdot BC, which is equivalent to the following linear algebraic formula:

B(x,y) -A(x,y) = \frac{1}{2}\cdot [C(x,y)-B(x,y)] (1)

B(x,y)-A(x,y) = \frac{1}{2}\cdot C(x,y)-\frac{1}{2}\cdot B(x,y)

\frac{3}{2}\cdot B(x,y) = \frac{1}{2}\cdot C(x,y)+A(x,y)

B(x,y) = \frac{1}{3}\cdot C(x,y) +\frac{2}{3}\cdot A(x,y) (2)

Then, the coordinates of point B on AC are:

B(x,y) = \frac{1}{3}\cdot (-3,-2)+\frac{2}{3}\cdot (6,-7)

B(x,y) = \left(-1, -\frac{2}{3}\right)+\left(4, -\frac{14}{3} \right)

B(x,y) = \left(3,-\frac{16}{3} \right)

Which means that correct answer is C.

5 0
3 years ago
Examine the system of equations.
MrMuchimi

answer:

x =  - 2 \\ y = 2 \\  \\ ( - 2, \: 2)

explanation:

y =  -  \frac{1}{2} x + 1 \\ y = 2x + 6 \\ first \: equation \: add \:  \frac{1}{2} from \: both  \\  sides \\   \\ second \: equation \: subtract \: 2x \: from  \\  both \: sides \\  \\ y +  \frac{1}{2} x = 1 \\ y - 2x = 6 \\ solve \: the \: first \: equation \\  \\ y +  \frac{1}{2} x = 1 \\ subtract \:  \frac{x}{2} from \: both \: sides \\  \\ y =  -  \frac{1}{2} x + 1 \\ substitute \:  -  \frac{x}{2}  + 1 \: for \: y \: in \: the  \\ other \: equation \\  \\  -  \frac{1}{2} x + 1 - 2x = 6 \\ add \:   \frac{1}{2} x \: to \: 2x \\  \\  -  \frac{5}{2} x + 1 = 6 \\ subtract \: 1 \: from \: both \: sides \\  \\  -  \frac{5}{2} x = 5 \\ divide \: both \: sides \: by \:  -  \frac{5}{2}  \\  \\ x =  - 2 \\ substitute \: the \: value \: of \: x \: into \\ an \: equation \\  \\ y =  -  \frac{1}{2} ( - 2) + 1 \\ distribute \\  \\ y = 1 + 1 \\ add  \\  \\ y = 2 \\  \\ ( - 2, \: 2)

7 0
3 years ago
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