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slamgirl [31]
2 years ago
8

94.248 is 30.6% of what number?

Mathematics
2 answers:
Lana71 [14]2 years ago
7 0
30.6% of 308 = 94.248
boyakko [2]2 years ago
6 0

Answer:

94.248 is 30.6% of <u>308</u>.

Step-by-step explanation:

The given problem asks us to find the number that represents the "<u><em>whole</em></u>" for which 94.248 is the 30.6% of its portion or "<u><em>part</em></u>."

In order to find that number, we must first transform 30.6% into its decimal form by moving the decimal point two places to the left:

30.6%  ⇒  0.306

Next, we must divide 94.248 by 0.306 to find the unknown number (because the opposite mathematical operation of multiplication is division):

\displaystyle\mathsf{\frac{94.248}{0.306}\:=\:308}

In order to verify whether 308 is the correct value of the unknown number that represents the "whole," simply multiply 94.248 by 0.306:

94.248 × 0.306 = 308  

Therefore, 94.248 is 30.6% of <u>308</u>.

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What are all the possible rectangles with whole-number side
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Step-by-step explanation:

The perimeter of a rectangle is P=2L+2W where L is the length and W is the width.

We have that P=10, so 10=2L+2W.

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2(5)=2(L+W)  I factored 10 as 2(5).

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Whole numbers are {0,1,2,3,4,5,6,7,8,9,10,...}. They are your counting numbers and 0.

I think they want natural numbers {1,2,3,4,...}.  This is also just called the counting numbers. The reason I think they want this because if one of the dimensions is 0, we won't actually have a rectangle.

So now looking for numbers from this set that satisfy: L+W=5.

L+W=5

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5 0
3 years ago
10. (a) Consider the following matrices: A = ( 2 ) B = (3) and C = (-3) w = Find the det(A). [1] (ii) Is the matrix A singular?
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ii) We have to find if the matrix A is singular.

Singular matrix have determinant equal to 0.

This is not the case for A, as its determinant is -12. Then, A is not a singular matrix.

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We have to write the matrix multiplication and we will obtain a system of linear equations:

We can now solve the system of equations by adding 3 times the second equation to the first equation:

\begin{gathered} 3(x-2y)+(3x+6y)=3(-3)+(-3) \\ 3x-6y+3x+6y=-9-3 \\ 6x+0y=-12 \\ x=\frac{-12}{6} \\ x=-2 \end{gathered}

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iv) Is not possible because the number of columns of the first matrix has to be equal to the number of rows of the second matrix.

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